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3 years ago

Factorise a^2-4ab+5b^2-c^2+6bc

Mathematics

1 answer:

Gennadij [26K]3 years ago

3 0

There is no way this is a middle school question

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3 years ago

Evaluate the expression for the given value of the variable. 51+5/8t T= -1/2

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811/16 i think

Step-by-step explanation:

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3 years ago

Talia’s Australian Shepherd weighed 11 pounds when they first brought him home. By the time he was 6 months old, he weighed 33 p

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Step-by-step explanation:

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2 years ago

Use the equation a = IaIâ

german

Answer:

a) $\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }$

b) $\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }$

c) $\:\:=7\cdot \frac{\:\:}{7}$

Step-by-step explanation:

a) Let a=<2,1,-3>

The magnitude of a is $|a|=\sqrt{2^2+1^2+(-3)^2}$

$|a|=\sqrt{4+1+9}=\sqrt{14}$

The unit vector in the direction of a is

$\hat{a}=\frac{\:\:}{\sqrt{14} }$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }$

b) Let a=2i - 3j + 4k

$|a|=\sqrt{2^2+(-3)^2+4^2}$

$|a|=\sqrt{4+9+16}=\sqrt{29}$

$\hat{a}=\frac{\:\:}{\sqrt{29} }$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }$

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

$|a|=\sqrt{3^2+6^2+(-2)^2}$

$|a|=\sqrt{9+36+4}=\sqrt{49}=7$

The unit vector in the direction of a is

$\hat{a}=\frac{\:\:}{7}$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=7\cdot \frac{\:\:}{7}$

5 0

3 years ago

1.272 divided by 0.003?

icang [17]

Answer:

the answer is 424

Step-by-step explanation:

you need to use long divison to find the number <3

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3 years ago

Factorise a^2-4ab+5b^2-c^2+6bc​

Factorise a^2-4ab+5b^2-c^2+6bc