The function has an **inverse **that is also a **function **is g(x) = 2x – 3.

The **correct option **is A.

<h3>Inverse function;</h3>

The **inverse **of a function is the **equation **where x and y have switched **places**.

We have to **determine**

Which **function **has an **inverse **that is also a function?

If when you solve for y again, the function **passes **the **vertical **line test, the **inverse **if a **function**.

1. Here g(x) = 2x - 3 has **inverse **x = 2y - 3 which **simplifies **to;

This is a **line **and is a **function**;

2. k(x) = -9x^2 has the **inverse **x = -9y^2 which **simplifies **to;

This is a **function **but only for certain values of **x**.

3. f(x) = |x+2| is an **absolute **value **function**.

All **absolute **value **functions **do not have inverses which are functions.

4. w(x) = -20 does not have an **inverse **which is a **function**.

Hence, the function has an **inverse **that is also a **function **is g(x) = 2x – 3.

To know more about **inverse function **click the link given below.

brainly.com/question/20663378

C = total number of candy

.4(c) = 8 pieces of candy

Divide c by .4: c= 20

20-8=12

Ed has 12 pieces of candy at home

-17(y - 2) = -17y + 64

Distribute the -17

-17y + 34 = -17y + 64

Add 17y to both sides

34 = 64

Once the variables cancel, and you end up with a FALSE statement, this means there are NO SOLUTIONS.

Elouise and Marcus are 20 km apart. There is a lake due west of Elouise that is also 10√3 km due north of Marcus, so 22.36 km **distance** the bearing of Marcus from Elouise.

<h3>What is Pythagoras theorem?</h3>

According to the Pythagoras theorem, the square of the hypotenuse of a right-angled triangle equals the sum of the squares of the other two sides. The formula for this theorem is c² = a² + b², where c is the **hypotenuse** and a and b are the **triangle's two legs**. Pythagoras theory triangles are another name for these triangles.

At first assume a triangle, In the triangle, assume Elouise at the point A and Marcus at the point B, and the lake at the C point.

Given that,

Elouise and Marcus are 20 km apart (AB)

There is a lake due west of Elouise that is also 10√3 km due north of Marcus (BC)

Now, according to a Pythagoras theorem,

(AC)² + (AB)² = (BC)²

or, (AC)² = (BC)²- (AB)²

or, (AC)² = (10√3)² - (20)²

or, AC =

or, AC = 22.36 km

So, distance bearing of Marcus from Elouise is 22.36 km.

To know more about **distance** refer to:

**brainly.com/question/13963928**

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