The function has an inverse that is also a function is g(x) = 2x – 3.
The correct option is A.
<h3>Inverse function;</h3>
The inverse of a function is the equation where x and y have switched places.
We have to determine
Which function has an inverse that is also a function?
If when you solve for y again, the function passes the vertical line test, the inverse if a function.
1. Here g(x) = 2x - 3 has inverse x = 2y - 3 which simplifies to;
This is a line and is a function;
2. k(x) = -9x^2 has the inverse x = -9y^2 which simplifies to;
This is a function but only for certain values of x.
3. f(x) = |x+2| is an absolute value function.
All absolute value functions do not have inverses which are functions.
4. w(x) = -20 does not have an inverse which is a function.
Hence, the function has an inverse that is also a function is g(x) = 2x – 3.
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C = total number of candy
.4(c) = 8 pieces of candy
Divide c by .4: c= 20
20-8=12
Ed has 12 pieces of candy at home
-17(y - 2) = -17y + 64
Distribute the -17
-17y + 34 = -17y + 64
Add 17y to both sides
34 = 64
Once the variables cancel, and you end up with a FALSE statement, this means there are NO SOLUTIONS.
Elouise and Marcus are 20 km apart. There is a lake due west of Elouise that is also 10√3 km due north of Marcus, so 22.36 km distance the bearing of Marcus from Elouise.
<h3>What is Pythagoras theorem?</h3>
According to the Pythagoras theorem, the square of the hypotenuse of a right-angled triangle equals the sum of the squares of the other two sides. The formula for this theorem is c² = a² + b², where c is the hypotenuse and a and b are the triangle's two legs. Pythagoras theory triangles are another name for these triangles.
At first assume a triangle, In the triangle, assume Elouise at the point A and Marcus at the point B, and the lake at the C point.
Given that,
Elouise and Marcus are 20 km apart (AB)
There is a lake due west of Elouise that is also 10√3 km due north of Marcus (BC)
Now, according to a Pythagoras theorem,
(AC)² + (AB)² = (BC)²
or, (AC)² = (BC)²- (AB)²
or, (AC)² = (10√3)² - (20)²
or, AC =
or, AC = 22.36 km
So, distance bearing of Marcus from Elouise is 22.36 km.
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