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Triss [41]
4 years ago
14

The annual Gross Domestic Product (GDP) of a country is the value of all of the goods and services produced in the country durin

g a year. During the period 1985-1999, the Gross Domestic Product of the United States grew about 3.2% per year, measured in 1996 dollars. In 1985, the GDP was $577 billion. I what year did/or will the GDP equal $1.6 trillion?
Mathematics
1 answer:
ZanzabumX [31]4 years ago
3 0
Given:
GDP = $577 billion = $0.577 trillion in 1985.
Annual growth rate = 3.2% = 0.032

After 1 year, the GDP will be  $ 0.577(1.032) trillion
After 2 years, the GDP will be $ 0.577(1.032)² trillion

...
After n years, the GDP will be $ 0.577(1.032)ⁿ trillion.

The number of years required from 1985 for the GDP to reach $ 1.6 trillion is
determined by
0.577(1.032)ⁿ = 1.6
1.032ⁿ = 1.6/0.577 = 2.773
n ln(1.032) = ln(2.773)
n = ln(2.773)/ln(1.032) = 32.4 years

From 1985, the year is
1985 + 32.4 = 2017.4

Answer:
The GDP will reach $1.6 trillion in the year 2017 if the average growth rate of 3.2% is maintained.



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A home improvement store buys snow shovels from a supplier for $8.50. The day before a snowstorm the store manager marks up the
balandron [24]

Answer:

The retail price is $15.30

Step-by-step explanation:

To solve this, turn the percentage into a decimal. Do this by dividing it by 100.

       180 ÷ 100 = 1.8

Then, multiply the supplier price by the decimal

      8.5 × 1.8 = $15.30

7 0
3 years ago
Find the domain of
ch4aika [34]

Answer:

C (x ≥ -6)

Step-by-step explanation:

<u>Algebraic:</u>

The domain of \sqrt{x} is x\geq 0. When transformed 6 units to the left, it becomes x\geq -6

<u>Graphically:</u>

As shown in the attached graph, x\geq -6 .

6 0
4 years ago
Which equations are related equations to x + 8 = 22?
andre [41]

Answer:

x=22+8 and x+22=8nd 8=22_x

8 0
3 years ago
Read 2 more answers
Hi, teacher I was absent these days and I didn’t understand anything about this lesson and I need help this is not count as a te
motikmotik

Given:

There are given that the cos function:

cos210^{\circ}=-\frac{\sqrt{3}}{2}

Explanation:

To find the value, first, we need to use the half-angle formula:

So,

From the half-angle formula:

cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+cos\theta}{2}}

Then,

Since 105 degrees is the 2nd quadrant so cosine is negative

Then,

By the formula:

\begin{gathered} cos(105^{\circ})=cos(\frac{210^{\circ}}{2}) \\ =-\sqrt{\frac{1+cos(210)}{2}} \end{gathered}

Then,

Put the value of cos210 degrees into the above function:

So,

\begin{gathered} cos(105^{\circ})=-\sqrt{\frac{1+cos(210)}{2}} \\ cos(105^{\operatorname{\circ}})=-\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}} \\ cos(105^{\circ})=-\sqrt{\frac{2-\sqrt{3}}{4}} \\ cos(105^{\circ})=-\frac{\sqrt{2-\sqrt{3}}}{2} \end{gathered}

Final answer:

Hence, the value of the cos(105) is shown below:

cos(105^{\operatorname{\circ}})=-\frac{\sqrt{2-\sqrt{3}}}{2}

4 0
1 year ago
PLEASEEE HURRYYY
Masteriza [31]

Answer:

(2,-5) and (2,1).

Step-by-step explanation:

We need to find the find all the points having an x coordinate of 2 whose distance from the point (-2,-4) is 5.

A circle with center (-2,-4) and radius 5 represents all the points whose distance from the point (-2,-4) is 5.

Standard form of a circle is

(x-h)^2+(y-k)^2=r^2

where, (h,k) is center and r is the radius.

(x-(-2))^2+(y-(-4))^2=(5)^2

(x+2)^2+(y+2)^2=25

Now, put x=2.

(2+2)^2+(y+2)^2=25

(4)^2+(y+2)^2=25

(y+2)^2=25-16

(y+2)^2=9

Taking square root on both sides.

y+2=\pm\sqrt{9}

y+2=\pm3

y+2=-3\text{ or }y+2=3

y=-5\text{ or }y=1

So, the y-coordinates of the points are -5 and 1.

Therefore, the required points are (2,-5) and (2,1).

8 0
3 years ago
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