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enot [183]
3 years ago
15

Please help me if so thank you

Mathematics
1 answer:
posledela3 years ago
6 0
Add 5 each time so A2 is going to be positive 1 A3 will be positive 6
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Help plz :( (plz show work) 3. Nancy invested $6000 in a bond at a yearly rate of 3%. She earned $450 in
sergij07 [2.7K]

Answer: 2years, 5 months

Step-by-step explanation:

Principal, P = $6000

Rate, R = 3%

Interest, I = $450

Time, T =?

Simple Interest, I = P x T x R/ 100

making T, subject of formula

T = 100 x I/ P x T

Substituting the values into the equation,

T = 100 x 450/ 6000 x 3

T = 45000/ 18000

T = 2.5years = 2years, 5 months

5 0
3 years ago
Pls help will give brainlest.
Arada [10]

2,400 in.³

I Love Maths :)

7 0
3 years ago
Read 2 more answers
How do I do question 9? Please give answer thank you
kvasek [131]
<h3>Given</h3>
  • a cone of height 0.4 m and diameter 0.3 m
  • filling at the rate 0.004 m³/s
  • fill height of 0.2 m at the time of interest
<h3>Find</h3>
  • the rate of change of fill height at the time of interest
<h3>Solution</h3>

The cone is filled to half its depth at the time of interest, so the surface area of the filled portion will be (1/2)² times the surface area of the top of the cone. The filled portion has an area of

... A = (1/4)(π/4)d² = (π/16)(0.3 m)² = 0.09π/16 m²

This area multiplied by the rate of change of fill height (dh/dt) will give the rate of change of volume.

... (0.09π/16 m²)×dh/dt = dV/dt = 0.004 m³/s

Dividing by the coefficient of dh/dt, we get

... dh/dt = 0.004·16/(0.09π) m/s

... dh/dt = 32/(45π) m/s ≈ 0.22635 m/s

_____

You can also write an equation for the filled volume in terms of the filled height, then differentiate and solve for dh/dt. When you do, you find the relation between rates of change of height and area are as described above. We have taken a "shortcut" based on the knowledge gained from solving it this way. (No arithmetic operations are saved. We only avoid the process of taking the derivative.)

Note that the cone dimensions mean the radius is 3/8 of the height.

V = (1/3)πr²h = (1/3)π(3/8·h)²·h = 3π/64·h³

dV/dt = 9π/64·h²·dh/dt

.004 = 9π/64·0.2²·dh/dt . . . substitute the given values

dh/dt = .004·64/(.04·9·π) = 32/(45π)

7 0
3 years ago
Please help will give brainliest
RUDIKE [14]

Answer:

Answer is c

Step-by-step explanation:

5 0
2 years ago
Graphs are everywhere in the news, but just because a graph is in print does not mean that it is trustworthy. Review the graph a
Contact [7]

Answer:

Kindly check explanation

Step-by-step explanation:

Taking a careful look at the graph above, the graph depicts that there is sizeable growth or increase in the rate of interest between 2008 to 2012. However, the actual increase in the rate of interest between 2008 - 2012 is (3.152% - 3.141%) = 0.011%. This change is very small compared to what is portrayed by the pictorial representation of the bar graph. This could be due to the scaling of the vertical axis which didn't start from 0, thereby exaggerating the increase in the actual rate of interest. It will thus mislead observers into thinking the increase is huge.

3 0
3 years ago
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