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Nookie1986 [14]
3 years ago
10

Let f(x)=ln(3x)+2.5 .

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
5 0
For this case what we should do is evaluate the function in each of the points from 2 to 7 and then find the average.
 We have then:
 f (x) = ln (3x) +2.5.
 f (2) = ln (3 * 2) + 2.5 = 4.291759469
 f (3) = ln (3 * 3) + 2.5 = 4.697224577
 f (4) = ln (3 * 4) + 2.5 = 4.98490665
 f (5) = ln (3 * 5) + 2.5 = 5.208050201
 f (6) = ln (3 * 6) + 2.5 = 5.390371758
 f (7) = ln (3 * 7) + 2.5 = 5.544522438
 Then the average is:
 Average = (4.291759469 + 4.697224577 + 4.98490665 + 5.208050201 + 5.390371758 + 5.544522438) / (6) = 5.019472516
 nearest hundredth
 5.02
 Answer:
 the average rate of change of f (x) from 2 to 7 is  5.02

ANTONII [103]3 years ago
4 0

Answer:

The answer is 0.25 I just took the quiz.

Step-by-step explanation:

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Step-by-step explanation:

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Which simplifications of the powers of i are correct? There may be more than one correct answer.
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\bf i^2=-1\qquad\qquad i^3=-i\qquad \qquad i^4=1 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ i^{22}\implies i^{(4\cdot 5)+2}\implies i^{4\cdot 5}i^2\implies (i^4)^5 i^2\implies 1^5(-1)\implies -1~\dotfill \bigotimes \\\\\\ i^{11}\implies i^{(2\cdot 5)+1}\implies (i^2)^5 i\implies (-1)^5(i)\implies -i~\dotfill \checkmark

\bf i^{21}\implies i^{(4\cdot 5)+1}\implies (i^4)^5 i\implies 1^5(i)\implies i~\dotfill \checkmark \\\\\\ i^{12}\implies i^{3\cdot 4}\implies i^3 i^4\implies (-i)(1)\implies -i\dotfill \bigotimes \\\\\\ i^{20}\implies i^{4\cdot 5}\implies (i^4)^5\implies 1~\dotfill \checkmark \\\\\\ i^{26}\implies i^{(4\cdot 6)+2}\implies (i^4)^6 i^2\implies 1^6(-1)\implies -1\dotfill \checkmark \\\\\\ i^{27}\implies i^{(4\cdot 6)+3}\implies (i^4)^6 i^3 \implies 1^6(-i)\implies -i\dotfill \bigotimes

6 0
3 years ago
Find tan A and tan B.
Alex

Step-by-step explanation:

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8 0
2 years ago
In a plot of probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum
Lunna [17]

In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.

<h3>What is an electron?</h3>
  • The electron is a subatomic particle with a negative one elementary charge electric charge.
  • Electrons are the first generation of the lepton particle family and are widely regarded as elementary particles due to the lack of known components or substructure.

Electron in the hydrogen:

  • Hydrogen has the simplest electron configuration to write because it just contains one electron.
  • There is essentially only one electron surrounding the Hydrogen nucleus.
  • Because hydrogen only has one electron, its configuration is 1s1.
  • The maximum occurs at a0, the first Bohr radius, in a plot showing the chance of finding the electron in the hydrogen ground state vs the distance from the nucleus.

Therefore, in a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.

Know more about electrons here:

brainly.com/question/860094

#SPJ4

The complete question is given below:

In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs:

A. at a0. the first Bohr radius

B. at slightly less than a0

C. at slightly more than a0

D. at 2 a0

E. at a0/2

6 0
1 year ago
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