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tatuchka [14]
3 years ago
11

What is the surface area of the regular pyramid? What is the surface area of a square pyramid with a height of 10.4 m and a base

side length of 12.4 m? a. 141.4 cm c. 167.4 m b. 162.4 cm d. 188.4 cm
Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer:

A. 141.4 cm

Step-by-step explanation:

The piramide is 141.4cm

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Order the numbers from least to greatest. 7.6, 7 8/21, 7 4/5, 7 2/3, 7.71
Ierofanga [76]

Answer:

7 8/21, 7.6, 7 2/3, 7.71, 7 4/5

Step-by-step explanation:

none

4 0
4 years ago
Read 2 more answers
Two cities have nearly the same​ north-south line of 110 degrees Upper W. The latitude of the first city is 23 degrees Upper F c
inn [45]

Answer:

CORRECTED QUESTION:

Two cities have nearly the same​ north-south line of 110 degrees Upper W. The latitude of the first city is 23 degrees Upper N, and the latitude of the second city is 36 degrees N. Approximate the distance between the cities if the average radius of Earth is 6400 km.

ANSWER: 1452.11 km

Step-by-step explanation:

Since the two cities both lies on the Northern latitude of the sphere along  the same longitude, we are going to subtract the angles the latitude that each city subtend at the equator.

36 - 23 = 13 degrees   i.e the angles between the with two cities on a cross section the large circle formed by the longitude and its center.

Applying   the formula for the length of an arc on a sector on the large circle  

(∅/ 360) x 2πR

where, ∅ = is the angle between the two cities

R = radius of the Earth.

13/360 x 2 x π x 6400 = 1452.11 km

7 0
3 years ago
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IrinaVladis [17]

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Step-by-step explanation:

5 0
3 years ago
Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
An aircraft flew 5 hours with the wind. The return trip took 6 hours against the wind. If the speed of the plane in still air is
Yakvenalex [24]

Answer:

Speed of wind = 23.63 miles per hour

Plane speed in still air = 260 miles per hour

Step-by-step explanation:

Given:

Time taken with wind = 5 hour

Time taken against wind = 6 hour

Assume;

Speed of wind = s

So,

Speed of Plane with wind = (260 + s) miles per hour

Speed of Plane against wind = (260 - s) miles per hour

Distance = speed x time

So,

(260 + s)5 = (260 - s)6

1,300 + 5s = 1,560 - 6s

11s = 260

s = 23.63 miles per hour

Speed of wind = 23.63 miles per hour

Plane speed in still air = 260 miles per hour

5 0
3 years ago
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