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mihalych1998 [28]

3 years ago

6

How much can 6 go in 3

2 answers:

vfiekz [6]3 years ago

8 0

Answer:

If you can go into fractions 6 can go into 3 half a time, but if you can't do that then say 6 can't go into 3.

Step-by-step explanation:

s344n2d4d5 [400]3 years ago

4 0

Answer: 6 cannot go into 3 because it is a larger number but 3 can go into 6 twice because 3x2=6

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If a b c=0, but abc don't equal 0, then a^2/bc b^2/ca c^2/ab=

goblinko [34]

$\sf a + b + c = 0\\abc \neq 0\\\\ \frac{a^2}{bc} + \frac{b^2}{ac} + \frac{c^2}{ab} = \frac{a^3+b^3+c^3}{abc} \\\\\sf Formula: \\a^3 + b^3 + c^3 = (a + b + c) (a^2 + b^2 + c^2- ab - bc - ca) + 3abc\\\\\frac{a^3+b^3+c^3}{abc}= \frac{(a + b + c) (a^2 + b^2 + c^2- ab - bc - ca) + 3abc}{abc}\\\\\sf However, ~a+b+c = 0. ~So:\\\\\frac{0 (a^2 + b^2 + c^2- ab - bc - ca) + 3abc}{abc}\\\\\sf Multiply~ anything ~by~ 0, ~and~ you ~get~ 0. ~So~ simplifying:\\\\\frac{3abc}{abc} = \boxed{3}$

Your final answer is 3.

3 0

3 years ago

Choose the statement that is not always true. for a rhombus

andreev551 [17]

Answer:

equal sides

Step-by-step explanation:

the side aren't always the same

6 0

3 years ago

Find the probability that his/her household has four or more cell phones in use. Is it unlikely for a household to have four or

sineoko [7]

Answer:

Event not unlikely

Step-by-step explanation:

Probability is defined as the likelihood of an event occurring.

$P(E)=Event/Total \ outcomes$

Total outcome, $T_o$ =Total responses record which is:

$T_o=218+296+362+148+142=1166$

$P_e=142$

Therefore the probability of 4+ phones is

$P(x\geq 4)=142/1166=0.1218$

Since $0.1218>0.05$ , the event is not unlikely

5 0

3 years ago

Flora made 4 withdrawals of $60 each from her bank account. What was the overall change in her

borishaifa [10]

The total change in her bank account would be 240, because you multiply 4 (amount of withdrawals) by 60(amount of cash). Hope this helps :)

3 0

3 years ago

Y varies directly with X and has a constant rate of change of 6. When the value of Y is 11, then the value of X could be _____.

Bogdan [553]

Answer: The correct option is (B) less than 2.

Step-by-step explanation: Given that Y varies directly with X and has a constant rate of change of 6.

We are to find the possible value of X when the value of Y is 11.

Since Y varies directly with X, so we can write

$Y\propto X\\\\\Rightarrow Y=kx~~~~~~~~~~~~~~~(i),~~~~~~~~~\textup{[where 'k' is the constant of variation]}$

Since the rate of change is constant and is equal to 6, so we must have

$k=6.$

So, from equation (i), we have

$Y=kX\\\\\Rightarrow Y=6X~~~~~~~~~~~~~~~~~~~~~~(ii)$

Now, when Y = 11, then from equation (ii), we get

$Y=6X\\\\\Rightarrow 11=6X\\\\\Rightarrow X=\dfrac{11}{6}$

Thus, the value of X is less than 2 when Y = 11.

Option (B) is CORRECT.

8 0

3 years ago