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3 years ago

How much can 6 go in 3

Mathematics

2 answers:

vfiekz [6]3 years ago

8 0

Answer:

If you can go into fractions 6 can go into 3 half a time, but if you can't do that then say 6 can't go into 3.

Step-by-step explanation:

s344n2d4d5 [400]3 years ago

4 0

Answer: 6 cannot go into 3 because it is a larger number but 3 can go into 6 twice because 3x2=6

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A 52 foot ladder is set against the side of the house so that it reaches up 48 feet .if jevonte grabs the ladder at its base and

Vesnalui [34]

Answer:

Step-by-step explanation:

The way to approach this that makes the most sense to a student would be to find out how far from the house the ladder currently is, then add 3 feet to that and do the problem all over again. This is right triangle stuff...Pythagorean's Theorem in particular. The ladder is the hypotenuse, 52 feet long. The height of the rectangle is the distance the ladder is up the side o the house, 48 feet. We plug those into Pythagorean's Theorem and solve for the distance the ladder is from the house:

$52^2=48^2+x^2$ and

$2704=2304+x^2$ and

$x^2=400$ so

x = 20. Now if we add the 3 feet that the ladder was pulled away from house, the distance from the base of the ladder to the house is 23 feet, the ladder is still 52 feet long, but what's different is the height of the ladder up the side of the house, our new x:

$52^2=23^2+x^2$ and

$2704=529+x^2$ and

$2175=x^2$ so

x = 46.6 feet

6 0

3 years ago

Please tell me !!!!!!

vlada-n [284]

Answer:

Step-by-step explanation:

Its H because a square has 4 sides and 58 divided by 4 is 14.5

8 0

3 years ago

A photograph is 4 inches high and 5 inches wide. You need to scale it up so it is 10 inches high. How wide should it be?

IrinaK [193]

Answer: 12.5 in. high

Step-by-step explanation: to get from 4 to 10, you have to muliplty by 2.5.

if you multiply 5 by 2.5, the answer is 12.5

8 0

4 years ago

Can someone please help me on number 16-ABC

melomori [17]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

-2x < 10

-6 < -2x

Part a) Is x = 0 a solution to both inequalities

FOR -2x < 10

substituting x = 0 in -2x < 10

-2x < 10

-3(0) < 10

0 < 10

TRUE!

Thus, x = 0 satisfies the inequality -2x < 10.

∴ x = 0 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 0 in -6 < -2x

-6 < -2x

-6 < -2(0)

-6 < 0

TRUE!

Thus, x = 0 satisfies the inequality -6 < -2x

∴ x = 0 is the solution to the inequality -6 < -2x

Conclusion:

x = 0 is a solution to both inequalites.

Part b) Is x = 4 a solution to both inequalities

FOR -2x < 10

substituting x = 4 in -2x < 10

-2x < 10

-3(4) < 10

-12 < 10

TRUE!

Thus, x = 4 satisfies the inequality -2x < 10.

∴ x = 4 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 4 in -6 < -2x

-6 < -2x

-6 < -2(4)

-6 < -8

FALSE!

Thus, x = 4 does not satisfiy the inequality -6 < -2x

∴ x = 4 is the NOT a solution to the inequality -6 < -2x.

Conclusion:

x = 4 is NOT a solution to both inequalites.

Part c) Find another value of x that is a solution to both inequalities.

solving -2x < 10

$-2x\:$

Multiply both sides by -1 (reverses the inequality)

$\left(-2x\right)\left(-1\right)>10\left(-1\right)$

Simplify

$2x>-10$

Divide both sides by 2

$\frac{2x}{2}>\frac{-10}{2}$

$x>-5$

$-2x-5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-5,\:\infty \:\right)\end{bmatrix}$

solving -6 < -2x

-6 < -2x

switch sides

$-2x>-6$

Multiply both sides by -1 (reverses the inequality)

$\left(-2x\right)\left(-1\right)$

Simplify

$2x$

Divide both sides by 2

$\frac{2x}{2}$

$x$

$-6$

Thus, the two intervals:

$\left(-\infty \:,\:3\right)$

$\left(-5,\:\infty \:\right)$

The intersection of these two intervals would be the solution to both inequalities.

$\left(-\infty \:,\:3\right)$ and $\left(-5,\:\infty \:\right)$

As x = 1 is included in both intervals.

so x = 1 would be another solution common to both inequalities.

<h3>SUBSTITUTING x = 1</h3>

FOR -2x < 10

substituting x = 1 in -2x < 10

-2x < 10

-3(1) < 10

-3 < 10

TRUE!

Thus, x = 1 satisfies the inequality -2x < 10.

∴ x = 1 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 1 in -6 < -2x

-6 < -2x

-6 < -2(1)

-6 < -2

TRUE!

Thus, x = 1 satisfies the inequality -6 < -2x

∴ x = 1 is the solution to the inequality -6 < -2x.

Conclusion:

x = 1 is a solution common to both inequalites.

7 0

3 years ago

6 = a/4 + 2 What’s the answer for the variable a?

Vikki [24]

Answer:

a = 16

Step-by-step explanation:

6 = a/4 + 2

4 = a/4 Subtract 2 from both sides

16 = a Multiply 4 to both sides

7 0

3 years ago

Read 2 more answers