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kati45 [8]
2 years ago
14

5. In how many ways can four boys and three girls be seated in a row con taining seven seats ( a ) if they may sit anywhere , (

b ) if the boys and girls must alternate ?​
Mathematics
1 answer:
hram777 [196]2 years ago
7 0
They can be sat 6 different ways
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You and some friends are going to the fair. Small rides costs 4 tickets and while big rides costs 7 tickets. You and your friend
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I need help learning how to solve this problem please.
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we have 4 gals, Stephanie, Andrea, Emily and  Becca.

btw the end point should be (-6, -7) and the start point is (8, 6).

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Emily's turn ends ¼ of the way later, which will be pretty much half-way in between  (1, -½) and (-6, -7), so is really the midpoint of those two.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;(\stackrel{x_1}{1}~,~\stackrel{y_1}{-\frac{1}{2}})\qquad&#10;\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}&#10;\\\\\\&#10;\left( \cfrac{-6+1}{2}~~,~~\cfrac{-7-\frac{1}{2}}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-14-1}{2}~}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-15}{2}~}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-5}{2}~,~\cfrac{-15}{4} \right)\implies \left( -2\frac{1}{2}~,~-3\frac{3}{4} \right)

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4 years ago
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