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2 years ago

Subtract. (2 + 5i) – (4 – 2i)

Mathematics

2 answers:

jeka57 [31]2 years ago

5 0

Answer:

7i - 2

Step-by-step explanation:

(2 + 5i) - (4 - 2i)

2 + 5i - 4 + 2i

2 - 4 + 7i

7i + 2 - 4

7i - 2

Assoli18 [71]2 years ago

3 0

Answer:

3i-2

Step-by-step explanation:

I am not sure it could also be, well I don't know.

Hopefully its correct, sorry if it not.

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2 years ago

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The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then

$\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v$

$\implies\ln|u|=\ln|v|+C$

$\implies\ln(y^2+4)=\ln|\ln x|+C$

$\implies y^2+4=e^{\ln|\ln x|+C}$

$\implies y^2=C|\ln x|-4$

$\implies y=\pm\sqrt{C|\ln x|-4}$

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2 years ago

ANSWER ASAP

Nadya [2.5K]

Bisector is simply a straight that divides the line (through which it's passing) into two equal halves. Or simply, it passes through the midpoint of any line. It may make any angle with the line through which it passes.

Perpendicular Bisector is also the same but the only difference is that it makes an angle of 90° with the line through which it passes or cuts.

3 0

1 year ago