The figure shows four forces exerted on a box. If F1 equals 4 N and F3 equals 6 N and the box remains stationary, which statemen
t is correct?
A- F2 equals 6 N and F4 equals 4 N.
B- F2 equals 2 N and F4 equals 10 N.
C- F2 equals 10 N and F4 equals 2 N.
D- F2 equals 4 N and F4 equals 6 N.
A- F2 equals 6 N and F4 equals 4 N.
B- F2 equals 2 N and F4 equals 10 N.
C- F2 equals 10 N and F4 equals 2 N.
D- F2 equals 4 N and F4 equals 6 N.
1 answer:
You might be interested in
Answer:
Therefore the probability that a pen from the first box and a crayon from the second box are selected is
Step-by-step explanation:
Probability:
The ratio of the number of favorable outcomes to the number all possible outcomes of the event.
Given that,
Three plain pencils and 5 pens are contained by the first box.
Total number of pens and pencils is =(3+5)=8
The probability that a pen is selected from the first box is
=P(A)
A second box contains three colored pencils and three crayons.
Total number of pencils and crayons is =(3+3)=6
The probability that a crayon is selected from the second box is
=P(B)
Since both events are mutually independent.
The required probability is multiple of the events
Therefore the required probability is