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galina1969 [7]
3 years ago
13

1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+1+1*1+(Just for fun)

Mathematics
2 answers:
irakobra [83]3 years ago
7 0

Answer:

23

Step-by-step explanation:

vladimir2022 [97]3 years ago
4 0
Ur answer is 54 i’m pretty sure
You might be interested in
Which of the following fractions is greater than -4/5 but less than -3/4
choli [55]

Answer:

B. -19/25

Step-by-step explanation:

You are looking for an answer that is greater than -4/5 (which is equal to -0.80) but less than -3/4 (which is equal to -0.75). So, you can easily convert the fractions to decimals by dividing.

-33/50 = -0.66, which is greater than -0.75, so it can be eliminated.

-19/25 = -0.76, which fits our parameters, so it is the answer.

-19/20 = -0.95, which is less than -0.80, so it can be eliminated.

-7/10 = -0.70, which is greater than -0.75, so it can be eliminated.

7 0
3 years ago
What is the area of the triangle?
blsea [12.9K]

Answer:

Step-by-step explanation:

Area=\frac{1}{2}bh

b ----> base of the triangle

h -----> perpendicular height of the triangle

3 0
3 years ago
Read 2 more answers
3x=3(3x+1)<br> x=(3x+1)<br> -2x=1<br> x=- 1/2
Gemiola [76]
You got the equation correct
6 0
3 years ago
Plz help me. I'm confused on hw​
r-ruslan [8.4K]
Answer: Yes by SAS

Why: they have two equal sides makes by the dashes and two 90 degree angles in the same places on both triangles meaning that the other side next to the 90 degree angle had to be equal as will

Hope this helps :D
4 0
2 years ago
2.What is the solution of the solution of the equation 5^3x=15? Round to the nearest ten thousandth.
sveta [45]
Hmm
remember
a^c=b can translate to log_a(b)=c
so

5^{3x}=15 can translate to log_5(15)=3x
divide both sides by 3
(1/3)log_5(15)=x
log_5(15^{1/3})=x
use calculator, if you can't use change of base formula to do it
log_a(b)= \frac{log_c(b)}{log_c(a)} so
log_5(10^{1/3})= \frac{log_{10}(15^{1/3})}{log_{10}(5)}=x
evaluate using base 10 on your calculator
0.560869=x
8 0
3 years ago
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