All categories

3 years ago

Use the intercepts to graph the equation. 7x-5y=35

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

3 0

Answer:

Step-by-step explanation:

well thats the graph 4 u

You might be interested in

Which choice is equivalent to the product below when x>=0? 20 pts

statuscvo [17]

Answer:

the required value which is equal to

$\sqrt{6x {}^{2} } \times \sqrt{3x \: } = 3x \sqrt{2x}$

Step-by-step explanation:

here's the explanation in attachment.

3 0

3 years ago

FASSTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT

Paraphin [41]

X=23

2x+14=60
2x=46
x=23

5 0

3 years ago

Read 2 more answers

When changing 67, 430,000 to scientific notation, how many places is the decimal point moved?

dmitriy555 [2]

Answer:

6.743*10^7

Step-by-step explanation:

Given data

The number is 67, 430,000

Let us count from the left the right

counting, we have 7 places to the right before the last digit 6

Hence the number of places is 7

The scientific notation is

=6.743*10^7

3 0

3 years ago

5. y = 3x + 9 y = 3(x + 3) I I No solution Infinite solutions

Natasha_Volkova [10]

Answer:

Infinite solutions

Step-by-step explanation:

3*x is 3x and 3*3 is 9

I used foil to make the equations look equal to each other.

since they're both equal to y you can set them equal to each other also.

3x+9=3(x+3)

3x+9=3x+9

bruh

8 0

4 years ago

The 2003 Zagat Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United Sta

levacccp [35]

Answer:

See explanation

Step-by-step explanation:

5 of 15 top-ranking restaurants offer dinner for more than $50 and 10 offer dinner for less than $50.

You will eat dinner at three of these restaurants.

a) The probability that none of the meals will exceed the cost covered by your company is

$\dfrac{C^{10}_3}{C^{15}_3}=\dfrac{\frac{10!}{3!(10-3)!}}{\frac{15!}{3!(15-3)!}}=\dfrac{10!\cdot 12!}{7!\cdot 15!}=\dfrac{8\cdot 9\cdot 10}{13\cdot 14\cdot 15}\approx 0.2637$

b) The probability that one of the meals will exceed the cost covered by your company is

$\dfrac{C^{10}_2\cdot C^5_1}{C^{15}_3}=\dfrac{\frac{10!}{2!(10-2)!}\cdot \frac{5!}{1!(5-1)!}}{\frac{15!}{3!(15-3)!}}=\dfrac{10!\cdot 5!\cdot 3!\cdot 12!}{2!\cdot 8!\cdot 4!\cdot 15!}=\dfrac{ 9\cdot 10\cdot 5\cdot 3}{\cdot 13\cdot 14\cdot 15}\approx 0.4945$

c) The probability that two of the meals will exceed the cost covered by your company is

$\dfrac{C^{10}_1\cdot C^5_2}{C^{15}_3}=\dfrac{\frac{10!}{1!(10-1)!}\cdot \frac{5!}{2!(5-2)!}}{\frac{15!}{3!(15-3)!}}=\dfrac{10!\cdot 5!\cdot 3!\cdot 12!}{9!\cdot 2!\cdot 3!\cdot 15!}=\dfrac{10\cdot 3\cdot 4\cdot 5}{13\cdot 14\cdot 15}\approx 0.2198$

d) The probability that all three of the meals will exceed the cost covered by your company is

$\dfrac{C^{5}_3}{C^{15}_3}=\dfrac{\frac{5!}{3!(5-3)!}}{\frac{15!}{3!(15-3)!}}=\dfrac{5!\cdot 12!}{2!\cdot 15!}=\dfrac{3\cdot 4\cdot 5}{13\cdot 14\cdot 15}\approx 0.0220$

8 0

4 years ago