Your answer is 0.00063371356147
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Answer:
NMO = 59
Step-by-step explanation:
If MO bisects LMN then LMO equals OMN
LMN = LMO+OMN
Since LMO = OMN
LMN = LMO + LMO
LMN = 2 LMO
Substituting LMN = 5x-22 and LMO = x+31
5x - 22 = 2( x+31)
Distribute
5x-22 = 2x+62
Subtract 2x from each side
5x-2x-22 = 2x-2x+62
3x-22 = 62
Add 22 to each side
3x-22+22 =62+22
3x = 84
Divide by 3
3x/3 = 84/3
x =28
LMO = x+31
=28+31
=59
NMO = LMO
NMO = 59
<h3>
Explanation:</h3>
Given:
- total score is 63
- field goals score 3
- touchdowns score 7
Find:
- a linear equation representing the relationships given
- a graph of that equation
- combinations of field goals and touchdowns that give the score
Solution:
1. see above for what is given
2. <em>Touchdowns and field goals can be represented by variables</em>. In the attachment, field goals are represented by x, and touchdowns are represented by y.
The score value of a field goal is 3, so the total score from x field goals can be written as the term 3x.
Likewise, the total score from y touchdowns can be written as the term 7y.
__
The equation of interest is then ...
3x + 7y = 63
The graph of it, and its integer solutions, is attached.
Possible combinations of (field goals, touchdowns) are ...
(0, 9), (7, 6), (14, 3), (21, 0)
Answer:
c: $7.09
Step-by-step explanation:
Both have a digit of 5 and at least two digits of 0
Both have factors of 2 and 5