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3 years ago

15

Multiply (5x^2-3x)(8x^2+4x

2 answers:

erastova [34]3 years ago

6 0

Ans

40x^4-4x^3-12x^2

Step-by-step explanation:

5x^2(8x^2+4x)-3x (8x^2+4x)

40x^4+20x^3-24x^3-12x^2

40x^4-4x^3-12x^2

Step2247 [10]3 years ago

3 0

Hope it will help u......

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X is directly proportional with Y write an equation that shows the relationship if y equals 6 and x equals one

KiRa [710]

Y=X+5 OR Y=6X CAN BE A EQUATION BUT YOU CAN FORM SOME MORE ALSO

7 0

3 years ago

____ [38]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

f(x) = 3x + x³

Taking differentiate

$\frac{d}{dx}\left(3x+x^3\right)$

$\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'$

$=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)$

solving

$\frac{d}{dx}\left(3x\right)$

$\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'$

$=3\frac{d}{dx}\left(x\right)$

$\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dx}\left(x\right)=1$

$=3\cdot \:1$

$=3$

now solving

$\frac{d}{dx}\left(x^3\right)$

$\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}$

$=3x^{3-1}$

$=3x^2$

Thus, the expression becomes

$\frac{d}{dx}\left(3x+x^3\right)=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)$

$=3+3x^2$

Thus,

f'(x) = 3 + 3x²

Given that f'(x) = 15

substituting the value f'(x) = 15 in f'(x) = 3 + 3x²

f'(x) = 3 + 3x²

15 = 3 + 3x²

switch sides

3 + 3x² = 15

3x² = 15-3

3x² = 12

Divide both sides by 3

x² = 4

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{4},\:x=-\sqrt{4}$

$x=2,\:x=-2$

Thus, the value of x will be:

$x=2,\:x=-2$

5 0

3 years ago

Angle 2 is 60. Find angle 8. <br><br> Options:<br> 140<br> 100<br> 40<br> 60

pav-90 [236]

Angle 8 is 60 too
eee

5 0

3 years ago

The line to the right goes through the point (6, y). If the angle the graph makes with the x-axis is 22°, what is

s344n2d4d5 [400]

Answer:

The y-coordinate of the point is approximately 2.42.

Step-by-step explanation:

From the figure attached below the statement we derive the following equation to calculate the y-coordinate ( $y$ ), dimensionless, of the point in terms of the x-coordinate ( $x$ ), dimensionless, and angle of the line ( $\theta$ ), measured in sexagesimal degrees:

$y = x\cdot \tan \theta$ (1)

If we know that $x = 6$ and $\theta = 22^{\circ}$ , then the y-coordinate of the point is:

$y = 6\cdot \tan 22^{\circ}$

$y\approx 2.42$

The y-coordinate of the point is approximately 2.42.

8 0

3 years ago

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B

marshall27 [118]

Answer:

IM preeetty sure the answer is x=4 and y=26 so the solution would be (4,26)

Step-by-step explanation:

hope this helps!!! <333

6 0

3 years ago

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