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Setler [38]
3 years ago
13

A bottle of shampoo costs $4 at a store. It is on sale for 25% off, and the sales tax in 5.5%. What is the sales price of the sh

ampoo?
please ACTUALLY HELP>DONT JUST SPAM >IM BEGGING U>I WORKED HARD FOR THESE POINTS>
Mathematics
2 answers:
Serjik [45]3 years ago
6 0

Answer:

1.22 dollars after sales tax

iVinArrow [24]3 years ago
6 0

Answer:

4

Step-by-step explanation:

that is the answer

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What is 25% of 10....
Gekata [30.6K]

Answer: 2.5

10 X 25%

25% = 25/100 = 0.25

10x0.25 = 2.5

Hope this helps!!

8 0
3 years ago
Read 2 more answers
Suppose 8x + 16 ice cream cones
kvv77 [185]

Answer:

B. 152 + 7

Step-by-step explanation:

(8x + 16) + (7x - 9)

8x + 16 + 7x - 9

15x + 16 - 9

15x + 7

None of these options have this answer, so we see A and B:

A. x + 7

B. 152 + 7

It can't be A because we have 15x and A is x + 7

By process of elimination we have B. 152 + 7

x = 10 and 2/15

8 0
2 years ago
F(x) = 3 x 2 − 3 x − 6 The domain of a the function f(x) is { -10, -1, 1, 5 }. What is the range of the relation?
jonny [76]

Answer:

{324, 0, -6, 54}

Step-by-step explanation:

Given that F(x) = 3x² − 3 x − 6 If the domain of a the function f(x) is { -10, -1, 1, 5 }.

To get the range, we will find f(x) for all the domains

at x = -10

f(-10) = 3(-10)²-3(-10) - 6

f(-10) = 3(100)-3(-10) - 6

f(-10) = 300+30-6

f(-10) = 330-6

f(-10) = 324

at x = -1

f(-1) = 3(-1)²-3(-1) - 6

f(-1) = 3(1)-3(-1) - 6

f(-1) = 3+3-6

f(-1) = 6-6

f(-1) = 0

at x = 1

f(1) = 3(1)²-3(1) - 6

f(1) = 3(1)-3(1) - 6

f(1) = 3-3-6

f(1) = 0-6

f(1) = -6

at x = 5

f(5) = 3(5)²-3(5) - 6

f(5) = 3(25)-3(5) - 6

f(5) = 75-15-6

f(5) = 60-6

f(5) = 54

Hence the range of the relation are {324, 0, -6, 54}

5 0
2 years ago
If k = 7 then find the value of 2k²
Leya [2.2K]

Answer:

98

Step-by-step explanation:

k = 7

2k^2

do the exponent

7 x 7 = 49

49 x 2 = 98

6 0
2 years ago
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How many zeros are in the product (6×5)×10
ohaa [14]
There are 2 zeros in the product because 6•5=30•10=300 so there are 2 zeros
5 0
3 years ago
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