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Nezavi [6.7K]
4 years ago
15

line passes through the point (0, –1) and has a positive slope. Which of these points could that line pass through? Check all th

at apply. (12, 3) (–2, –5) (–3, 1) (1, 15) (5, –2)
Mathematics
2 answers:
sammy [17]4 years ago
8 0

Answer:

Points passing though are (12, 3),(–2, –5) and (1, 15)

Step-by-step explanation:

For a line passing through (x₁,y₁) and (x₂,y₂) slope is given by \frac{y_2-y_1}{x_2-x_1}.

Here we have one point (0, –1), we need to check slope of all the points given.

(12, 3)

          m=\frac{3-(-1))}{12-0}=\frac{1}{4}>0

(–2, –5)

          m=\frac{-5-(-1))}{-2-0}=\frac{-4}{-2}=2>0

(–3, 1)

         m=\frac{1-(-1))}{-3-0}=\frac{2}{-3}=-\frac{2}{3}

(1, 15)

        m=\frac{15-(-1))}{1-0}=\frac{16}{1}=16>0

(5, –2)

        m=\frac{-2-(-1))}{5-0}=\frac{-1}{5}=-\frac{1}{5}

Points with positive slope are (12, 3),(–2, –5) and (1, 15)

Iteru [2.4K]4 years ago
8 0

Answer:

A. (12, 3)

B. (–2, –5)

D. (1, 15)

Step-by-step explanation:  For a line passing through (x₁,y₁) and (x₂,y₂) slope is given by .

Here we have one point (0, –1), we need to check slope of all the points given.

(12, 3)

         

(–2, –5)

         

(–3, 1)

        

(1, 15)

       

(5, –2)

       

Points with positive slope are (12, 3),(–2, –5) and (1, 15)

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Answer:

The Equation:

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Step-by-step explanation:

<u>Things you need to know:</u>

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Need to know point slope form of a linear equation y - y_1 = x(x - x_1)

Ok, with that out the way, lets get started!

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<u>Insert our point and slope into y - y_1 = x(x - x_1) and solve for y</u>

y - y_1 = x(x - x_1)

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<u>Work on the right side of the = sign</u>

Distribute 1/3 to x and 7

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<u>Bring the 10 over to the right side by adding a -10</u>

y + 10 -10= \frac{1}{3}x + \frac{7}{3} - 10

y = \frac{1}{3}x + \frac{7}{3} - 10

Do the math for \frac{7}{3} - 10 = -\frac{23}{3}

y = \frac{1}{3}x - \frac{23}{3}

<u>We are done.</u>

The Equation:

y = \frac{1}{3}x - \frac{23}{3}

The y-intercept:

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