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serious [3.7K]
4 years ago
11

A rock is thrown in the air from the edge of a seaside cliff. Its height in feet is represented by f(x) = –16(x2 – 3x – 18), whe

re x is the number of seconds since the rock was thrown. The height of the rock is 0 feet when it hits the water.How long does it take the rock to hit the water? How many seconds?
Mathematics
2 answers:
enyata [817]4 years ago
5 0
Set the given equation equal to zero (0), since that's the height of the rock when it hits the water:

0 = -16(x^2 - 3x - 18)  (Note:  Please write x^2 to denote "square of x.")

Solving this equation for x, we get:

0 = -16(x-6)(x+3), and x=-3 or x=6.  Since x represents time, discard the negative value x=-3.

The rock hits the water after 6 seconds.
Tatiana [17]4 years ago
5 0

It hit the water at 6 seconds (APEX)

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natta225 [31]

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14.46% probability that the instructor can finish grading in 4 and a half hours

Step-by-step explanation:

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Normal probability distribution

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Central Limit Theorem

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In this problem, we have that:

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Z = -1.06 has a pvalue of 0.1446

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