$\bf \displaystyle \int~\cfrac{sec^2(x)}{\sqrt{1+tan(x)}}\cdot dx\\\\
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u=1+tan(x)\implies \cfrac{du}{dx}=sec^2(x)\implies \cfrac{du}{sec^2(x)}=dx\\\\
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\displaystyle \int~\cfrac{\underline{sec^2(x)}}{\sqrt{u}}\cdot\cfrac{du}{\underline{sec^2(x)}}\implies \int~\cfrac{1}{\sqrt{u}}\cdot du\implies \int~u^{-\frac{1}{2}}\cdot du
\\\\\\
2u^{\frac{1}{2}}\implies 2\sqrt{1+tan(x)}+C$

6 0

3 years ago

Read 2 more answers

I NEED HELP. PLEASE ANSWER QUICK. BRAINLIEST WILL BE GIVEN. THERE IS A BOT AUTO ANSWERING. PLEASE ANSWER ANYWAY

dimaraw [331]

Answer:

The answer is A

Step-by-step explanation:

The shape is a rhombus when plotted on a quardanent plane. The shape is similar to a diamond.

7 0

3 years ago

Translate the phrase into an algebraic expression.<br> The quotient of w and 4

Lady_Fox [76]

W/4 divide the two to find the quotient

4 0

3 years ago

Helppppppppppppppppppppppppp

Wewaii [24]

Answer:

Radius: 8

Circumference: 50.27

πr^2 = Area of circle

201.06 = πr^2

divide by pi

201.06 / π = 63.9993857161 = 64

64 = r^2

Square root both sides to get radius.

$\sqrt{64}$ = 8

r = 8

Circumference = π x diameter

Diameter = 2 x radius

Circumference = π x 16 = 50.2654824574 = 50.27

8 0

3 years ago