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satela [25.4K]
3 years ago
14

Of the 350 seniors at Westside High School, 1/25 plan to attend junior college in the fall. Which represents the part of seniors

who plan to attend junior college?
A. 1/25
B. 0.40
C. 25/350
D. 0.04
Mathematics
2 answers:
STatiana [176]3 years ago
6 0
1/25, easy
also, 1/25=4/100=0.04/1=0.04

A and D
Jermaine2 years ago
0 0

I think the answer is c

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74.94×103= <br> because the number 10³ has ?<br> zeros when it is written without an exponent.
horsena [70]

Answer:

74940, three

Step-by-step explanation:

74.94 × 10³

74.94 × 1000

74940

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3 years ago
A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi
SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

= \frac{20!}{(20-5)! 5!)}

= \frac{20*19*18*17*16}{5*4*3*2*1}

= 15504

b) probabilities of A2, A5, A4

P(A2) = ⁵C₂ / ²⁰C₂

= \frac{20}{320} = \frac{1}{19}

P(A5) = ⁸C₅ / ²⁰C₅

= \frac{56}{15540} = \frac{7}{1938}

P(A4) = ⁷C₄ / ²⁰C₄

= \frac{35}{4845} = \frac{7}{969}

c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1

5 0
3 years ago
Find the value of x using the measures of the two given adjacent
asambeis [7]
3x+ 54=180
straight angle is 180
So just solve the equation.
subtract 54 on both sides.
126=3x
divide that by 3, and you get 42.
check You answer by multiplying 42 And 3, Which basically Is 126
and then 126+54
which is then 180
7 0
3 years ago
BC has a midpoint at M(6, 6). Point C is at (2, 10). Find the coordinates of point B.
agasfer [191]

Answer:

The coordinates of B are (10,2)

Step-by-step explanation:

Hi there!

We know that BC has a midpoint M, with the coordinates (6,6), and the endpoint C, with coordinates (2, 10)

We want to find the coordinates of point B

The midpoint formula is (\frac{x_1 + x_2}{2}, \frac{y_1+ y_2}{2}), where (x_1, y_1) and (x_2 , y_2) are points. In this case, the point C has the values of (x_1, y_1), and B has the values of (x_2 , y_2)

We know that coordinates of M equal (\frac{x_1 + x_2}{2}, \frac{y_1+ y_2}{2})

In other words,

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Let's plug 2 for x_1 and 10 for y_1

So:

\frac{2 + x_2}{2} = 6\\ \frac{10+ y_2}{2}=6

Multiply both sides by 2

{2 + x_2} = 12\\{10+ y_2} =12

Subtract 2 from both sides in the first equation to find the value of x_2:

x_2=10

Now, for the second equation, subtract 10 from both sides to find the value of y_2

y_2=2

Now substitute these values for (x_2, y_2)

(x_2, y_2)=(10,2)

So the coordinates of point B are (10, 2)

Hope this helps!

3 0
3 years ago
Match the base to the corresponding height.
allochka39001 [22]

Answer:

I can't see the picture

Step-by-step explanation:

SORRY :(

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