Answer:
a. 4(d+3e)
b. 6(3x+5y)
c. 7(3a+4y)
d. 8(3f+7g)
Step-by-step explanation:
In each case we find the greatest common factor of the numbers. That is the greatest number that goes into both the numbers. Then we factor it out in front and inside parentheses we divide each original term by the greatest common factor:
a. 4d+12e, GCF: 4
b. 18x+30y, GCF: 6
c. 21a+28y, GCF: 7
d. 24f+56g, GCF: 8
Answer:
a repeating term of .3
Step-by-step explanation:
1/3 = 1 divided by 3
1 divided by 3 = .33333333333333333333
that is called a repeating term
= .3
Answer:
4
Step-by-step explanation:
If we plot that point we find ourselves in QIV. The distance along the x axis is 4, and the distance down from that point is -3. If we create a right triangle with that segment, that segment serves as the hypotenuse of the triangle. We need its measure. Using Pythagorean's theorem,
and
. We see that c = 5. We need now to find the secant of that right triangle. Secant if the co-identity of cosine which is side adjacent over hypotenuse. That means that secant is the hypotenuse over the side adjacent. So our secant theta = 5/4
Answer:
120
Step-by-step explanation:
Plug in variables with numbers
2(8+2)*6
2(10)*6
20*6
120
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