Ask question

Ask question

All categories

3 years ago

9

in this line of circles, the ratio of the red circles to blue circles is 1:3. how many more red circles would need to be added t

o make the ratio of red to blue 3:1

1 answer:

Tems11 [23]3 years ago

5 0

Answer:

Step-by-step explanation:

If we assume that initially

Number of red counter is 1

Number of blue counter is 3

Now to make ratio reverse you need to add 8 more red counters so that ratio becomes

9:3=3:1

You might be interested in

SERIOUSLY HELPPPPPPPP

AlekseyPX

9514 1404 393

Answer:

B.

as x increases, f(x) decreases;
as x decreases,f(x) decreases

Step-by-step explanation:

The function is of even degree with a negative leading coefficient. f(x) will tend toward negative infinity as x gets larger or smaller. That is ...

as x increases, f(x) decreases;
as x decreases,f(x) decreases

_____

<em>Even degree</em> means the end behaviors are the same for both large and small x. <em>Negative leading coefficient</em> means the function value decreases for larger x.

8 0

3 years ago

Is -8.56 a rational or irrational number?

PolarNik [594]

Its a rational number

5 0

3 years ago

Read 2 more answers

A person is given one push on a tire swing and then allowed to swing freely. On the first swing the person travels a distance of

Colt1911 [192]

How many times were they swung? 0.0 .....
if swung twice.. I think the answer would be 27.16

.

6 0

3 years ago

PLEASE HELP ASAP

Tju [1.3M]

Answer:

$y^2 + 2y + 80$

Step-by-step explanation:

$6y^2 + 2y + 5 - (5y^2 - 64 - 11)$

$6y^2 + 2y + 5 - 5y^2 + 64 + 11$ [pay attention to the signs :)

$y^2 + 2y + 80$

5 0

2 years ago

An automobile dealer had 288 cars and trucks in stock during the month. He must pay an inventory fee of 52 per car and $5 per tr

Aleonysh [2.5K]

For the given conditions, we won’t get a practical solution.

<u>Solution:</u>

Given, An automobile dealer had 288 cars and trucks in stock during the month.

He must pay an inventory fee of 52 per car and $5 per truck.

He paid $849 for inventory foes.

We have to find how many cars and Trucks did he have during the month?

Now, let the number of trucks be n, then number of cars will be 288 – n

And, according to given information,

$\begin{array}{l}{5 \times n+52 \times(288-n)=849} \\\\ {\rightarrow 5 n+52 \times 288-52 n=849} \\\\ {\rightarrow 52 n-5 n=14976-849} \\\\ {\rightarrow 47 n=14127} \\\\ {\rightarrow n=300.57}\end{array}$

Here we got n > number of cars and trucks, which is practically impossible.

Hence, for the given conditions, we won’t get a practical solution

8 0

3 years ago