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Sphinxa [80]
3 years ago
15

rt{2} \frac{7}{8}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
quester [9]3 years ago
5 0

Answer:

\sqrt{2\frac{7}{8} } =\\\sqrt{\frac{25}{8} } =\\\sqrt{\frac{25*2}{16} } =

±5√2/4

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Evaluate x-2 for x = -3.
Vadim26 [7]
X-2 for x=-3
-3-2=-5, add dem negatives
8 0
3 years ago
Please help!!!!!!<br> Find the radical equivalent 8-2/3 and compute It.
Aleksandr-060686 [28]

Answer:

2.71

Step-by-step explanation:

Given 8 - 2/3 = 8(3/3) - 2/3 = 24/3 - 2/3 = 22/3 = 7.333 then the radical is

7.333**(1/2) = 2.71

4 0
3 years ago
OK i have a problem i have to find the percentage that the price went up so i have .57 cents and then it went up to 62 cents sho
cluponka [151]
It would be ab 8.77%

3 0
3 years ago
How do I write Domain and Range in inequality notation?
ArbitrLikvidat [17]

Answer:

Domain: (-infinity, infinity)    Range:  (-infinity, infinity)

Step-by-step explanation:

They are parabolas, therefore you can assume that they go on infinitely. To find range, you must look at your y values. Look for your lowest point. Because the line goes done forever, your beginning mark would be (-infinity.

To find the other part, you look at your positive y values. Look for the highest value. Because this goes on infinitely, the completed version of your notation would be (-infinity, infinity). Be sure to use the infinity symbol though, which looks like an 8 rotated 90 degrees.


To find domain, look at your x values. To begin, look at your left-most values, which would be the negative numbers. Because the line goes on forever to the left, your notation would be (-infinity. To find the other part of domain, look at your positive x values. Because this line goes on infinitely as well, the completed version of your notation would be (-infinity, infinity). Infinity is never bracketed, it is always in parenthesis.

8 0
3 years ago
If g(x)=4x-6 then g^-1(x)=?<br> (1) -4x+6<br> (2)-1/4x+1/6<br> (3)1/4x+3/2<br> (4)1/4x+6
kati45 [8]

Given:

g(x)=4x-6

To find:

The function g^{-1}(x).

Solution:

we have,

g(x)=4x-6

Put g(x)=y.

y=4x-6

Interchange x and y.

x=4y-6

Isolate y.

x+6=4y

\dfrac{x+6}{4}=y

y=\dfrac{x+6}{4}

Substitute y=g^{-1}(x).

g^{-1}(x)=\dfrac{x+6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{3}{2}

Therefore, the correct option is (3).

4 0
3 years ago
Read 2 more answers
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