Answer: a = 1 b = 7
Step-by-step explanation:
x^2(y^3)^4/x.y^5 = x^a.y^b
x^2(y^12) = x^a.y^b
(x^2).(y^12)/x^y^5 = x.y^7
x.y^7= x^a . y^b -> <u>x^1.y^7</u>
Answer:
<u>x = (3√34 + 1)/5 units</u>
Step-by-step explanation:
Let's solve for x, using the Pythagorean theorem, this way:
BC is the Hypotenuse of the triangle ABC
BC² = 15² + 9²
BC² = 225 + 81
BC² = 306
BC = √9 * 34
BC = 3 √34
Now, we can substitute and solve for x, this way:
BC = 3x + 2x - 1
3 √34 = 3x + 2x - 1
3√ 34 + 1 = 5x
<u>x = (3√34 + 1)/5 units</u>
Answer
t f
Step-by-step explanation:
Answer:
9. y = 8
10. n = 21
11. 44 = v
12. c = 35
Step-by-step explanation:
9. 9y = 72
Divide each side by 9
9y/9 = 72/9
y = 8
10. 3n = 63
Divide each side by 3
3n/3 = 63/3
n = 21
11. 4 = v/11
Multiply each side by 11
4*11 = v/11*11
44 = v
12. c/7 = 5
Multiply each side by 7
c/7*7 = 5*7
c = 35
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Can a function be concave down and positive everywhere?can be a semicircle
example, y=4+

attachment 1
Can a function be increasing and be concave down everywhere?no, concave down means increase slope then decrease slope
Can a function have two local extrema and three inflection points?inflection points are where the concavity changes
it can be at the ends, the middle and the other end
like in atachment 2, the circles are inflection points
Can a function have 4 zeros and two local extrema?
no, as you can see in attachment 3, there can be 3 zeroes at most for 2 local extrema
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