Answer:
To the nearest hundred dollars, the car will be worth $17,900 by 2005
Step-by-step explanation:
Firstly, we need to write the depreciation equation
We have this as:
V = I(1 - r)^t
V is the present value which is what we want to calculate
I is the initial value, the amount the cad was bought which is $22,000
r is the rate of change which is 5% = 5/100 = 0.05
t is the time difference which is 2005-2001 = 4
Substituting all these into the depreciation equation, we have it that
V = 22,000(1 -0.05)^4
V = $17,919.1375
To the nearest hundred dollars, that would be;
$17,900
If you simply it down you get

so X can technically be any number
The answer is: y = -3/2 x + 8
Graph:
To find the answer we use the formula;
y-y1 = M1 (x - x1)
y-2 = -3/2 (x-4)
When fully solved: the answer is:
y = -3/2 x + 8
Answer:
Step-by-step explanation:
The answer is A