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I am Lyosha [343]
3 years ago
15

How do you set up this problem? Your class sells boxes of oranges to raise $500 for a field trip. You earn $6.25 for each box of

oranges sold. Write and solve an inequality that represents the number of boxes your class must sell to meet or exceed the fundraising goal.
Mathematics
1 answer:
Kazeer [188]3 years ago
3 0
You would divide the about of money you made by the amount each box costs.

$500÷6.25=80

80 boxes were sold

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erastova [34]
2. $9.20 cause you multiply the price by the number of the sweets
8 0
3 years ago
Read 2 more answers
Find x<br><br> A. X = 23<br> B. X = 31<br> C. X = 62<br> D. X = 118
Scorpion4ik [409]

Answer:

A

Step-by-step explanation:

6x-20= 118

6x= 118 + 20

6x = 138

x = 138/6

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8 0
3 years ago
Solve for x. x - 2(2 - 3/2 x) = 2(4 - x) + 1
STALIN [3.7K]

Answer:

x = 13/6

Step-by-step explanation:

We are the following expression;

       x - 2(2 - (3/2)*x) = 2(4 - x) + 1

       x - (4 - 3*x) = 8 - 2*x + 1

       x - 4 + 3*x = 8 - 2*x + 1

         4*x + 2*x = 9 + 4

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8 0
3 years ago
Pls answer this with a picture showing the correct box plot
faust18 [17]

Answer/Step-by-step explanation:

To find out the mistake of the student, let's find the min, max, median, Q1 and Q3, which make up the 5 important values that are represented in a box plot.

Given, {2, 3, 5, 6, 10, 14, 15},

Minimum value = 2

Median = middle data point = 6

Q1 = 3 (the middle value of the lower part of the data set before the median)

Q3 = 14 (middle value of the upper part of the data set after the median)

Maximum value = 15

If we examine the diagram the student created, you will observe that he plotted the median wrongly. The median, which is represented by the vertical line that divides the box, ought to be at 6 NOT 10.

See the attachment below for the correct box plot.

3 0
3 years ago
1. Pedro is a good student.<br> a.<br> b.
ICE Princess25 [194]

Answer:

your answer is (A)

Step-by-step explanation:

in the affirmative

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5 0
3 years ago
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