Write the quadratic equation in general form. (x - 3)^ 2 = 0
2 answers:
The answer is: x² – 6x + 9 = 0 . _____________________________________________________ Explanation:________________________________________________________ Given: (x – 3)² = 0 ; write as: general form: "ax² + bx + c = 0"; a ≠ 0 . <span> Note: </span>(x – 3)² = (x – 3)(x – 3) = x² – 3x – 3x + 9 = x² – 6x + 9 ; ___________________________________________________ Rewrite: (x – 3)² = 0 ; → as: x² – 6x + 9 = 0 ; which is our answer. ____________________________________________ → x² – 6x + 9 = 0 ; is in "general form", or "standard equation format"; that is: " ax² + bx + c = 0 "; (a ≠ 0) ; → in which: a = 1 (implied coefficient, since anything multiplied by "1" is that same value); b = -6; c = 9_______________________________________________________
Easy expand (x-3)^2=0 (x-3)(x-3) foil first: x time x=x² outter: -3 times x=-3x inner:x times -3=-3x last: -3 times -3=9 add them x²-3x-3x+9=0 x²-6x+9=0
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