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DiKsa [7]
3 years ago
7

Point E has a positive y-coorsinate Where could point E be located on the coordinate plane?​

Mathematics
1 answer:
Andrej [43]3 years ago
5 0

Answer:

A. Quadrant I

B. Quadrant II

F. y-axis

Step-by-step explanation:

If Point E has a positive y-coordinate then point E could be located on the top quadrants (quadrants 1 and 2) and the y-axis.

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3 years ago
Which statement represents the expression 11 (30 + 7)?
allochka39001 [22]

Answer:

330+77= 407

Step-by-step explanation:

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Marcus randomly draws tokens from a bag containing 10 blue tokens, 8 green tokens, and 12 red tokens. The first draw is a green
IrinaVladis [17]

Answer: 1. D) 30

2. A) 8

3. B) 4/15

4. A)  2/9

5.D) 64%

Step-by-step explanation:    

1. Since, here the tokens from a bag containing 10 blue tokens, 8 green tokens, and 12 red tokens. The first draw is a green token.

Thus, the total token = 10 blue tokens+ 8 green tokens+ 12 red tokens = 30 token

Therefore, If the first draw is a green token, Then total outcomes that will possible = 30.

2. Since, getting green is an event with 8 favorable outcomes.

Therefore,  If the first draw is a green token, Then total favorable outcomes that will possible = 8.

3. The possibility of getting green in first drawn, P(G) = \frac{8_C_1}{30_C_1}

P(G) =  \frac{8}{30} = \frac{4}{15}

4. Here, Number of red socks= 5

Number of white socks = 2 and Number of  blue socks=3

Therefore total socks = 10

⇒ Probability of picking a pair of red socks,

P(R)= \frac{5_C_2}{10_C_2} = \frac{10}{45}

⇒ P(R)= 2/9

5. Since, here coin is flipped 50 times and lands on heads 32 times.

Therefore, experimental probability that coin will land on heads on the next flip = (total times in which head appears/ total number of experiments) × 100 = (32/50)×100=64%


3 0
3 years ago
Bonnie’s Baskets purchases $4,000 worth of office equipment on account. This causes A. Cash and Capital to decrease. B. Office E
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3 0
3 years ago
The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f
Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen  who carry a credit card balance.

The formula for the interval is:

p'₁±Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }

Z_{1-\alpha /2}= Z_{0.95}= 1.648

0.37±1.648*\sqrt{\frac{0.37*0.63}{1000} }

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂±Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }

0.48±1.648* \sqrt{\frac{0.48*0.52}{1000} }

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: \sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015

Seniors: \sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0
3 years ago
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