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Vladimir [108]
3 years ago
15

A secant is a line or segment that passes through a circle in one and only one place. True or false?

Mathematics
1 answer:
mixas84 [53]3 years ago
4 0
False. Secant enters circle in one point and exits circle in other point. There are infinite number of pairs on which that can be done. So there isnt only one pair of places. Just remember that it has to enter and exit circle...
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Please help asap! i need to find the missing coordinate
Harrizon [31]

Answer:

8 or 32

Step-by-step explanation:

So we are given two coordinates and the length of the segment formed by those coordinates.

To find the unknown coordinate, we can use the distance formula. Let the unknown value be n:

Let's let (-2,n) be x₁ and y₁ and let (-7,20) be x₂ and y₂.

The distance formula is given by the formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-2,n) for x₁ and y₁ and (-7,20) for x₂ and y₂. Also, since we already know that the length is 13, substitute it for d. Thus:

(13)=\sqrt{((-7)-(-2))^2+((20)-(n))^2}

Do the operations within the parentheses:

13=\sqrt{(-7+2)^2+(20-n)^2}\\13=\sqrt{(-5)^2+(20-n)^2}

Now, square both sides to take out the square root:

(13)^2=(\sqrt{(-5)^2+(20-n)^2})^2

Simplify:

169=(-5)^2+(20-n)^2

Square (-5):

169=25+(20-n)^2

Subtract 25 from both sides. The right cancels:

(169)-25=(25+(20-n)^2)-25\\144=(20-n)^2

Now, take the square root of both sides.

\pm\sqrt{144}=\sqrt{(20-n)^2}

Simplify:

\pm12=(20-n)

So, we have two solutions:

(12=20-n)\text { or }(-12=20-n)

On the left, subtract 20. On the right, also subtract 20:

(-8=-n)\text { or }(-32=-n)

Divide both sides by -1:

(n=8)\text{ or } (n=32)

So, our two possible answers are 8 or 32.

5 0
3 years ago
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