Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1
Answer:
1 or 2
Step-by-step explanation:
one of the parentaziz has to equal 0 because anything multiplies by 0 is 0
Factor:
Solution: a^2 + ac + ba + bc ========>Answer: (a + b)(a + c)
Factor:
a^2 + ac + ba + bc
a^2 + ab + ac + bc
=(a + b)(a + c)
Answer: =======> (a + b)(a + c)
Hope that helps!!!! : )