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pogonyaev
3 years ago
8

Paid the rent for the month,$650

Mathematics
1 answer:
agasfer [191]3 years ago
3 0

Answer:

whats the question here

Step-by-step explanation:650 rent

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50 point! Look at the picture attached. I will mark brainliest!
worty [1.4K]

Answer:

22°

Step-by-step explanation:

Triangle KJL ≅ Triangle MJL (RHS)

[JL = JL(common), KL = LM(given), angle KLJ = angle MLJ(given)]

we come up to the conclusion that 4x + 6 = 3x + 10

x = 4

∴angle KJL = 4(4) + 6 = 22°

6 0
3 years ago
Read 2 more answers
Simplify 3^5/3^2.<br> I do have a basic understanding but I need help on this.
ahrayia [7]
The answer is:  " 27 " .
__________________________________________

3⁵ / 3² = 3⁽⁵⁻²⁾ = 3³ = 3 * 3 * 3 = 9 * 3 = 27 .
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-Edit -- Note the following property of exponents :  "quotient rule" of exponents:
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Given that "a" and "b" are positive integers; and that "x" is a real number greater than "zero"; 
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  If a <span>≥ b ,  then:

   x</span>ᵃ /xᵇ = x⁽ᵃ ⁻ ᵇ⁾ ;
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If a <span>< b , then:
</span>
xᵃ /xᵇ = x⁽ᵇ ⁻ ᵃ⁾
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7 0
4 years ago
Write an equation representing the pound of clay, c, that jamal from the example needs to make b bowls.
Inessa [10]

Answer:

8=2/3c

Step-by-step explanation:

Each bowl requires 2/3 pounds of clay

To make 8 bowls, Jamal needs 5 1/3 pounds of clay

4 0
2 years ago
A train travels a total of 38 km at a constant speed of 90 km/h. How long is its journey? Give your answer in minutes and second
brilliants [131]

Answer:

3420 minutes 205,200 second.

4 0
3 years ago
Rút gọn biểu thức sau
Artemon [7]

Answer:

Step-by-step explanation:

\left(3+\frac{\frac{9}{2}}{\sqrt{5}}\right)\left(2-\sqrt{5}\right)n+\left(3-\frac{\frac{9}{2}}{\sqrt{5}}\right)\left(2+\sqrt{5}\right)

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\times \:a}

=\left(\frac{9}{2\sqrt{5}}+3\right)\left(2-\sqrt{5}\right)n+\left(-\frac{\frac{9}{2}}{\sqrt{5}}+3\right)\left(2+\sqrt{5}\right)

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\times \:a}

=\left(\frac{9}{2\sqrt{5}}+3\right)\left(2-\sqrt{5}\right)n+\left(-\frac{9}{2\sqrt{5}}+3\right)\left(2+\sqrt{5}\right)

=\frac{-12-9\sqrt{5}}{2\sqrt{5}}n+6n+\left(3-\frac{9}{2\sqrt{5}}\right)\left(2+\sqrt{5}\right)

=\frac{-12-9\sqrt{5}}{2\sqrt{5}}n+6n+\frac{12-9\sqrt{5}}{2\sqrt{5}}+6

=\frac{\sqrt{5}\left(\left(3\sqrt{5}-12\right)n+12-9\sqrt{5}\right)}{10}+6

4 0
3 years ago
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