2 years ago

How to find where the equations meet.

1 answer:

3 0

The first sentence → x - 2y = -1
the second one → 3x - 2y = -3

multiply the first one by -1
you can get → -x + 2y = 1

plus two sentences together
you can get → 2x = -2

so you are able to know that x = -1
and y = 0

You might be interested in

Please help me I'm on a time crunch

Neporo4naja [7]

You multiple it by 20....
1:20
2:40
3:60
4:80
5:100
So it’s 80 inches by 100 inches (80x100) =800 square feet

8 0

2 years ago

Read 2 more answers

LAST ATTEMPT! MARKING AS BRAINLIEST!! ( simplifying radicals)

klasskru [66]

$\huge \bf༆ Answer ༄$

Let's solve ~

$\qquad \looparrowright \sf - 2 \sqrt{192 {k}^{4} }$

$\qquad \looparrowright \sf - 2 \sqrt{2 {}^{6} \times 3{k}^{4} }$

$\qquad \looparrowright \sf - 2 \times 2 {}^{3} \times {k}^{2} \times \sqrt{3}$

$\qquad \looparrowright \sf - 16 {k}^{2} \sqrt{3}$

Hence, the correct choice is D

5 0

2 years ago

Read 2 more answers

Prove this trigonometric equation; - tan^2x + sec^2x = 1,

alekssr [168]

Hey there :)

- tan²x + sec²x = 1 or 1 + tan²x = sec²x

sin²x + cos²x = 1
Divide the whole by cos²x

$\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}$

$\frac{sinx}{cosx} = tanx$ so $\frac{sin^2x}{cos^2x} = tan^2x$
and
$\frac{1}{cosx} = secx$ so $\frac{1}{cos^2x} = sec^2x$

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0

2 years ago

Me+You=? wanna test our equation? ;3

Vika [28.1K]

Hahaha anyway thanks for the free point

5 0

2 years ago

Read 2 more answers

7.1 + 16.04 – .2 = ? A. 23.34 B. 2.294 C. 23.12 D. 22.94

tamaranim1 [39]

The answer you're looking for my good lad is C

6 0

2 years ago

Read 2 more answers