First, let's turn all the numbers into improper fractions so that we can find the answer easier.
-2 
= r - 
-
= r -
Now we have to isolate 'r'.
First, we have to make sure that the variable is on one side and all the numbers are on the other side.
To do this, we have to add to both sides.
In order to do this, we need to ensure that both fractions have a common denominator.
- = r -
Ensure that the denominators are the same:
= r - 
+ = r
= r
Good luck!
The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
<h3>How to represent the
quadratic function in standard form?</h3>
The quadratic function is given as
f(x) = -3x^2 + 6x - 2
The standard form of a quadratic function is represented as:
f(x) = ax^2 + bx + c
When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form
Where
a = -3
b = 6
c = -2
Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
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Answer:
and 
Step-by-step explanation:
when you solve for r in the given equation, you need to apply the square root property, which gives positive and negative answers (both should therefore be considered):
then you need to include these two possible solutions:
and
