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NISA [10]
2 years ago
6

What is the value of x in the figure below?

Mathematics
1 answer:
zhenek [66]2 years ago
7 0
Again, nice problem. These are not super easy. You need to imagine the triangles in the figure and relate sides.

For instance: ADC, its hypotenuse is 15

For ABC, it is 20,

so 20/15 is the ratio between both triangles. Now let's choose the side with 'x'

x is one side of ADC, the corresponding side in ABC is 15 (the second longest sides). You need to rotate the triangles, etc ... That's the tricky part :)

So:

20/15 =15/x ----> x = 15*15/20 = 225/20 = 45/4

Which is C

Not sure whether it's too late to help you though!!!!

Also notice that it's kind of a product rule:

x * 20 = 15 * 15

I am sure the book explains a short way of getting to this equation, like sides opposite, blah blah, but what i told you is the reason. You asked for understanding it! Best luck!
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<h3><u>Answer</u>:- </h3>

\longrightarrow \sf \$ \: 307.2

<h3><u>Solution:-</u></h3>

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

\green{ \underline { \boxed{ \sf{Surface \: area  \:of  \:Cube = 6a^2}}}}

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\begin{gathered}\\\quad \sf Surface \: area  \:of  \:Cube = 6\times(3.2)^2  \\\end{gathered}

\begin{gathered}\\\implies \quad \sf  6\times 3.2\times3.2   \\\end{gathered}

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\maltese \sf Cost  \:of  \:painting \: 1 \: cm² = \$ 5

\sf Cost \: of \: painting \: 61.44  \:cm²=61.44×5

\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2

\leadstoThus it would cost $ 307.2 to paint the entire cubical block.

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