Answer:

Step-by-step explanation:

Adding 10 to both sides.


Adding
to both sides.


Dividing both sides by 10.


∴ 
Answer:
<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>
<u>IQR for town B, 10.</u>
Step-by-step explanation:
IQR = Q₃ - Q₁
For the town A:
Q₃ = 40 and Q₁ = 20
IQR of town A = 40 - 20 = 20
For the town B:
Q₃ = 30 and Q₁ = 20
IQR of town A = 30 - 20 = 10
Check the given options:
The most statement is appropriate comparison of the spreads is B
<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>
<u>IQR for town B, 10.</u>
<u />
A) 60 Clown fish / 5 = 12
12 x 4 = 28 Angel fish
B) 28 Angel fish / 4 = 12
12 x 3 = 36 Gold fish
C) Add all fish 28 Angel fish + 36 Gold fish + 60 Clown fish = 124 Fish in total
Answer:
Habían inicialmente 84 vacas. Murieron 36 vacas. 24 vacas fueron vendidas.
Step-by-step explanation:
Sea
la cantidad inicial de vacas. De acuerdo con el enunciado, murieron tres séptimos de la cantidad inicial y la mitad de ese remanente fue vendida, quedando 24 vacas. Matemáticamente, tenemos las siguientes operaciones:
Cantidad inicial de vacas

Habían inicialmente 84 vacas.
Cantidad de vacas muertas


Murieron 36 vacas.
Cantidad de vacas vendidas


24 vacas fueron vendidas.