We want to solve the Initial Value Problem y' = y + 4xy, with y(0) = 1.
To use Euler's method, define
y(i+1) = y(i) + hy'(i), for i=0,1,2, ...,
where
h = 0.1, the step size.,
x(i) = i*h
1st step.
y(0) = 1 (given) and x(0) = 0.
y(1) ≡ y(0.1) = y(0) + h*[4*x(0)*y(0)] = 1
2nd step.
x(1) = 0.1
y(2) ≡ y(0.2) = y(1) + h*[4*x(1)*y(1)] = 1 + 0.1*(4*0.1*1) = 1.04
3rd step.
x(2) = 0.2
y(3) ≡ y(0.3) = y(2) + h*[4*x(2)*y(2)] = 1.04 + 0.1*(4*0.2*1.04) = 1.1232
4th step.
x(3) = 0.3
y(4) ≡ y(0.4) = y(3) + h*[4*x(3)*y(3)] = 1.1232 + 0.1*(4*0.3*1.1232) = 1.258
5th step.
x(4) = 0.4
y(5) ≡ y(0.5) = y(4) + h*[4*x(4)*y(4)] = 1.258 + 0.1*(4*0.4*1.258) = 1.4593
Answer: y(0.5) = 1.4593
Answer:
Step-by-step explanation:
Answer:
x= 2
Step-by-step explanation:
the shapes are 6 in apart
Answer:
A = 104 ft²
Step-by-step explanation:
We're given that the width of the rectangle is 8 so that's the value of w. All we have to do is just plug in 8 into the equation:
A=w²+5w
A=(8)²+5(8)
A=64+40
A = 104 ft²
Answer:9a^2+18a-72
Step-by-step explanation:
9(a+1)^2-81
9(a+1)(a+1)-81
Open brackets
9(a^2+a+a+1)-81
9(a^2+2a+1)-81
9a^2+18a+9-81
9a^2+18a-72
