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Sliva [168]
2 years ago
10

Decrease R1400 in the Ratio 7:3​

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
8 0

Answer:

Step-by-step explanation:

It's hard to tell what you mean. I'm going to assume you mean that you want what is left to be 3/7 less.

1400 - 3/7 1400 = 1400 - 600 = 800

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A bag contains six red and ten black marbles if you pick a marble from the bag what is the probability that the marble will be b
dimulka [17.4K]

Answer:

125

Step-by-step explanation:

The total number of marbles is 6+10 = 16

P (black) = black / total

               = 10/16  = 5/8

With 200 draws, take the probability of P(black) times 200 since the marble is returned each time

200 * (5/8) = 125

We would expect to get 125 black marbles

6 0
3 years ago
Hannah has another candle that is 14 cm tall. How fast must it burn in order to also be 6 cm tall after 4 hours? Explain your th
RideAnS [48]

Answer:

The candle must burn at 2cm per hour in order to be 6cm tall after 4 hours. I know this because the candle has to burn 8cm in 4 hours and that amounts to 2cm per hour.

Step-by-step explanation:

Lets solve!

We have to find out how much of the candle needs to be burned!

14cm - 6cm = 8cm

The candle must burn 8cm in 4 hours!

Lets find out how much the candle burns in 1 hour.

\frac{8cm}{4hours}= 2cm per hour

The candle must burn at 2cm per hour in order to be 6cm tall after 4 hours. I know this because the candle has to burn 8cm in 4 hours and that amounts to 2cm per hour.

Woohoo, We did it! <u>Would you like to mark my answer as brainliest?</u> I would love that!

6 0
3 years ago
(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
3 years ago
How do I solve this problem?
nexus9112 [7]
Subtract the second equation from the first equation.
x = -1
Plug -1 back in to either equation and solve for y.
3(-1) + y =-10
-3 + y = -10
Add 3 to both sides
y = -7
CHECK
3(-1) -7 = -10
2(-1) -7 = -9
(-1, -7)
5 0
3 years ago
You have ​$23 comma 000 to​ invest, part at 8 % and the rest at 9 %. If x is the amount invested at 8 %​, write an algebraic exp
Vinvika [58]

<em>x</em> = amount invested at 8 %. Then 23 000 - <em>x</em> = amount invested at 9 %

Annual income (<em>I</em>) = interest at 8 % + interest at 9 %

<em>I</em> = 0.08<em>x</em> + 0.09(23 000 – <em>x</em>)

<em>I</em> = 0.08<em>x</em> + 2070 – 0.09<em>x</em>

<em>I</em> = 2070 – 0.01<em>x</em>

3 0
3 years ago
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