The side lengths of the cube are 8cm. I found this answer by taking the cube root of 512.
The link leads to a single table, and that table doesn't show [ y = 18x ].
You're looking for a table in which each 'y'-value is
18 times the 'x'-value that's right next to it.
Good luck in your quest.
THE ANSWER IS: 86 degrees
first find the measure of angle a: since all angles of a triangle add up to 180, add the measures of angle b and angle c then subtract it from 180 to get angle a: 62+54=116, 180-116=64
since we know line AD bisects angle a, we can divide 64 degrees by 2 to find angle BAD: which is 32 degrees
then subtract both 62 and 32 from 180 to get 86 degrees for angle ADB
b
Take a look at everything inside the brackets sqrt(50x^2) = sqrt(5*5*x*x * 2) For ever 2 factors you can bring one out and drop the other one. That means take out 5 * x * sqrt(2). Two is what is left inside the brackets. B must = 2.
c
Do the same thing here. Write all the primes under the square root. Take out 1 for every two under the root sign. sqrt(32x) = sqrt(2*2*2*2*2*x) You can bring out two 2s. There is one left over. Leave it under the root sign. The x is a loner. It stays under the root sign. c = 2 * 2 = 4.
e
Again do the prime factor thing. sqrt(18n) = sqrt(3*3*2*n) = 3*sqrt(2*n)
e = 3
g
sqrt(72*x*x) = sqrt(3 * 3* 2 * 2 * 2 * x * x) = 3 *2 * x* sqrt(2) For every 2 prime factors you can pull out 1 of them outside the square root sign. g = 6
Comment
There are many people on the net and on Brainly that will say that you should know the perfect squares from 1 to 100 (say) so 4 9 16 25 36 49 64 81 100 are the numbers that you should memorize. When they are under the root sign, their roots can be taken out as 2 3 4 5 6 7 8 9 10. For this question I think it is better to use the pairs rule I've given you above. If someone else answers they are likely to do it the way it is written up in this paragraph. It's a free country. You are free to take the answer you like best.
This will give you many results. AP = PB by construction
C is a point made by making the compass points such that AC>AP and the compass points are not altered so that BC = AC
C when joined to P creates a perpendicular line. This is very important. You use it a lot.
