1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ksivusya [100]
3 years ago
7

A cell phone provider offers a plan that costs ​$40 per month plus ​$0.20 per text message sent or received. A comparable plan c

osts ​$60per month but offers unlimited text messaging. Complete parts a. and b. below. a. How many text messages would have to be sent or received in order for the plans to cost the same each​ month? In order for the plans to cost the​ same,____ text messages would have to be sent or receive
Mathematics
2 answers:
GalinKa [24]3 years ago
6 0
So what times .2 equals 20
100 messages
Ivahew [28]3 years ago
6 0
60 - 40 = 20
20 / .20 = 100
100 text messages would have to be sent or received. 
You might be interested in
a light bulb consumes 6300 watt hours in 3 days and 12 hours. how many watt hours does it consume per day
Oksana_A [137]

Answer:

1800 watt hours

Step-by-step explanation:

6300 watt hours in 3 days and 12 hours

3 x 24 = 72 3 days worthof hours

72 + 12 = 84 total hours

6300/84 = 75 watt hours per hour

75 x 24 = 1800 watt hours per day

6 0
3 years ago
Fran purchased an annuity that provides $5,400 quarterly payments for the next 10 years. The annuity was purchased at a cost of
guajiro [1.7K]

Answer:

$5400

Step-by-step explanation:

Gross income is any interest, wage etc(money received) given to someone which they account for before any deductions and tax. Fran will have to include all $5400 of her first quarterly payment into her gross income because there are no deductions yet and tax when you consider what is put in gross income. Fran would have earned this amount as a payment from the purchasing of the annuity as it serves as a payment back for purchasing an annuity which to Fran, is an investment.

4 0
3 years ago
Look at the Schoology problem provided below.
lys-0071 [83]

Answer:

k = 4 units

Step-by-step explanation:

Using Pythagoras' identity on the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

k² + 7.5² = 8.5²

k² + 56.25 = 72.25 ( subtract 56.25 from both sides )

k² = 16 ( take the square root of both sides )

k = \sqrt{16} = 4

6 0
3 years ago
Read 2 more answers
HELP PLEASE!!! I don’t understand these math questions at all and it’s due in 2 hours, I’m freaking out
nataly862011 [7]

Answer:

1. The top and bottom lines (-5,3) (8,3) is parallel to line (-2,-2) (11,-2). The sides Lines (-5,3) (-2,-2) is parallel to line (8,3) (11,-2).

2. None of the line create a right angle. None are able to create a box at the angle

4 0
3 years ago
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
Other questions:
  • Classify each polygon by its number of sides. Drag the choices into the boxes to correctly classify each polygon
    8·1 answer
  • Is this relation a function?
    15·1 answer
  • Use the formula d = rt to find the value of the missing variable.<br> d = 130 ​feet, t = 26 seconds
    13·1 answer
  • Parallel to y + 8x = 4 through (3, 4) ; slope-intercept form
    10·1 answer
  • According to the diagram which of the following statement is true?
    14·1 answer
  • How much material is needed to make a triangular flag with base 2 1/4 and height 8 1/2
    13·1 answer
  • 2) A ray is a geometric figure that consist of
    10·1 answer
  • John flew a kite. He started flying the kite at 2:20 pm and ended at 3:14 pm. How many minutes did John fly a kite?
    13·2 answers
  • What is 4(7k + ( -2a) + 3a + 4)
    8·1 answer
  • A lender estimates the closing costs on a home loan will be 3.75% of the loan amount of $120,000. the actual closing costs are l
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!