Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s
Answer:
can u write the question
Step-by-step explanation:
pls the I will answer it
2 and 3/5 + 1 and 1/8
First, find the LCM of 5 and 8: 40
Next, make equivalent fractions:
2 and 24/40 + 1 and 5/40= 3 and 29/40
Answer: 3 and 29/40
Answer:
I think it is B or D
actually it is B i got 100%
Step-by-step explanation:
