Answer:
540
Step-by-step explanation:
divide 15 by 2.5 then multiply that answer by 90
The probability of selecting exactly one ace is its likelihood
The probability that a five-card poker hand contains exactly one ace is 29.95%
<h3>How to determine the probability?</h3>
There are 4 aces in a standard deck of 52 cards.
The probability of selecting an ace would be:
p = 4/52
Also, there are 48 non-ace cards in the standard deck
So, the probability of selecting a non-ace after an ace has been selected is:
p = 48/51
The probability of selecting a non-ace up to the fifth selection are:
- After two cards have been selected is: 47/50.
- After three cards have been selected is: 46/49.
- After four cards have been selected is: 45/48.
The required probability is then calculated as:
P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Where n is the number of cards i.e. 5
So, we have:
P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Evaluate
P(1 Ace) = 0.2995
Express as percentage
P(1 Ace) = 29.95%
Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%
Read more about probability at:
brainly.com/question/25870256
Answer:
The restocking level is 113 tins.
Step-by-step explanation:
Let the random variable <em>X</em> represents the restocking level.
The average demand during the reorder period and order lead time (13 days) is, <em>μ</em> = 91 tins.
The standard deviation of demand during this same 13- day period is, <em>σ</em> = 17 tins.
The service level that is desired is, 90%.
Compute the <em>z</em>-value for 90% desired service level as follows:
*Use a <em>z</em>-table for the value.
The expression representing the restocking level is:
Compute the restocking level for a 90% desired service level as follows:
Thus, the restocking level is 113 tins.
Simplified: 6x^3- 30x^2+3x
Hope this is helpful. :)
