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diamong [38]
3 years ago
5

The difference of a number and 9 •write as a algebraic expression

Mathematics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

x - 9

Step-by-step explanation:

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MARKING BRAINLIEST !! please help asap !
guajiro [1.7K]

Answer:

78

Step-by-step explanation:

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8 0
3 years ago
the length of one of the diagonals of a quadrilateral is 10 cm and the particular drawn from the opposite vertices to this diago
loris [4]

Answer:

Therefore the area of the quadrilateral =35 cm²

Step-by-step explanation:

Given, the length of one of diagonal of quadrilateral is 10 cm and perpendicular drawn from the opposite vertices to this diagonal are the length of 2.8 cm and 4.2 cm.

A diagonal divided a quadrilateral into two triangle.

Therefore the area of the quadrilateral

= sum of the area of the triangles

=(\frac{1}{2}\times 10\times 2.8+ \frac{1}{2}\times 10\times 4.2)cm²      [ area of a triangle= \frac{1}{2}\times base\times height]

=35 cm²

3 0
3 years ago
Geometry math question no Guessing and Please show work thank you
Lelu [443]

DE + EF = 4x+2

DE = x+7

EF = 7

Substitute these in

x + 7 + 7 = 4x + 2

x + 14 = 4x + 2

subtract x from both sides

14 = 3x + 2

subtract 2 from both sides

3x = 12

divide both sides by 3

x = 4

substitute this in to find the length of DE

DE = x + 7

(4) + 7 = 11

the answer is 11

5 0
3 years ago
Read 2 more answers
HELP ASAP <br> H(x)=-6x+8<br> G(x)=10-2x<br><br> H(G(x))
galben [10]

<u>Answer:</u>

H(G(x)) = 12x - 52

<u>Step-by-step explanation:</u>

We are given the following two functions:

H ( x ) = - 6 x + 8

G ( x ) = 1 0 - 2 x

And we are to find the value of H(G(x)).

For that, we will apply the function of H on the function of G.

H(G(x))=H(10-2x)

H ( G ( x ) ) = - 6 ( 1 0 - 2 x ) + 8

H(G(x))=-60+12x+8

H(G(x)) = 12x - 52

7 0
3 years ago
374 exceeds three times a number by 74
Assoli18 [71]
374>3x+74\\374=74>3x\\300>3x\ /:3\\100>x\\Ans.\ x
3 0
3 years ago
Read 2 more answers
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