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daser333 [38]
2 years ago
13

The graph shown below expresses a radical function that can be written in

Mathematics
1 answer:
Naddika [18.5K]2 years ago
6 0

Answer:

the graph shows that the correct answer is going to be C because it makes the most sense

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Find the slope-intercept form of the equation of the line that passes through the point (5,1) and is perpendicular to the line 2
Vlad1618 [11]

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

Convert 2x + 5y = 10 to the slope0intercept form:

2x+5y=10        <em>subtract 2x from both sides</em>

5y=-2x+10       <em>divide both sides by 5</em>

y=-\dfrac{2}{5}x+2

Let k:y=m_1x+b_1 and l:y=m_2x+b_2

l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}

We have m_1=-\dfrac{2}{5}

Therefore

m_2=-\dfrac{-\frac{2}{5}}=\dfac{5}{2}

We have the equation of a line:

y=\dfrac{5}{2}x+b

Put the coordinates of the point (5, 1) to the equation of a line:

1=\dfrac{5}{2}(5)+b

1=\dfrac{25}{2}+b       <em>subtract \dfrac{25}{2} from both sides</em>

-\dfrac{23}{2}=b\to b=\dfrac{23}{2}

Answer: \boxed{y=\dfrac{5}{2}x+\dfrac{23}{2}}

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