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3 years ago

How do I solve this

Mathematics

1 answer:

Levart [38]3 years ago

8 0

You could make a graph. one part of the graph would show the max number of cooler tubes he could get with that money and the other side would show how many normal tubes he could get with the money. about everything in between should work too

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Which of the following tables represents a function?<br> A. *|- 11 -5 -4 1

tekilochka [14]

Answer: Option A

Step-by-step explanation:

A relation between two variables x and y is considered a function if and only if, for each input value x there is only one output value y.

If for an input value $x_0$ there are two output values $y_1$ and $y_2$ then the relation is not a function.

Therefore, to answer this question, identify the table in which each value of x has only one value of y.

You may notice that the option that meets this requirement is option A

Note that in option B, there are two output values 17 and 16 for x = -4.

So this relationship is not a function.

In option C there are 2 output values for x = -5

In option D there are 2 output values for x = -11

7 0

3 years ago

A random sample of 64 students at a university showed an average age of 20 years and a sample standard deviation of 4 years. The

adelina 88 [10]

Answer:

The 90% confidence level is $19.15< L < 20.85$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 64$

The mean age is $\= x = 20 \ years$

The standard deviation is $\sigma = 4 \ years$

Generally the degree of freedom for this data set is mathematically represented as

$df = n - 1$

substituting values

$df = 64 - 1$

$df = 63$

Given that the level of confidence is 90% the significance level is mathematically evaluated as

$\alpha = 100 - 90$

$\alpha =$ 10 %

$\alpha = 0.10$

Now $\frac{\alpha }{2} = \frac{0.10}{2} = 0.05$

Since we are considering a on tail experiment

The critical value for half of this significance level at the calculated degree of freedom is obtained from the critical value table as

$t_{df, \frac{ \alpha}{2} } = t_{63, 0.05 } = 1.669$

The margin for error is mathematically represented as

$MOE = t_{df , \frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

substituting values

$MOE = 1.699 * \frac{4 }{\sqrt{64} }$

$MOE = 0.85$

he 90% confidence interval for the true average age of all students in the university is evaluated as follows

$\= x - MOE < L < \= x + E$

substituting values

$20 - 0. 85 < L < 20 + 0.85$

$19.15< L < 20.85$

4 0

3 years ago

When four digits (between 0 and 9 inclusive) are randomly selected with replacement for a lottery ticket, what is the probabilit

Assoli18 [71]

We are asked to determine the probability of having at least one digit of zero in a winning lottery number that is composed of four digits from the set of numbers from 0 to 9. To determine the probability to be known, we can approach this problem by computing for the probability by counting theory for each digit.

Digit 1: there are 10 choices, so the probability is 1/10
Digit 2: there are only9 choices, probability of 1/9
Digit 3: there are also 9 choices, probability of 1/9
Digit 4: 9 digits as 0 is not a included

*(numbers beginning with zero do not count zero as part of the number)

Hence the probability is (1/10)*(1/9)*(1/9)*(1/9) = <span>0.000137</span>

4 0

3 years ago

Free Brainliest to whoever answers first :)))

Delicious77 [7]

Answer:

hihihihihihihihihihi

7 0

3 years ago

Read 2 more answers

Help me answer this question

Zigmanuir [339]

Answer:

3.5

Step-by-step explanation:

27/3=9 and 18/3 is 6 so 10.5/3 is 3.5

8 0

3 years ago