Ask question

Ask question

All categories

3 years ago

9

2 Points

1 answer:

Mashcka [7]3 years ago

5 0

Answer:

C. It would be shifted up.

Step-by-step explanation:

We base it off the y-intercept. Since -7 is <em>less</em><em> </em><em>than</em><em> </em>1, and our new function has a positive y-intercept, it would indeed be shifted up.

I am joyous to assist you anytime.

You might be interested in

Find the extreme values of the function and where they occur. f(x)=x-4sqrt(x)

Tema [17]

The extreme values of the function f(x) = x - 4sqrt(x) occur at the values of x for which f'(x) = 0

f'(x) = 1 - 2/sqrt(x) = 0
sqrt(x) - 2 = 0
sqrt(x) = 2
x = 4
To check for minimum or maximum,
f''(x) = 1/(sqrt(x))^3 = 1/(sqrt(4))^3 = 1/(2^3) = 1/8 => the point is a minimum.

Therefore, the minimum value = f(4) = 4 - 4sqrt(4) = 4 - 4(2) = 4 - 8 = -4 and occurs at x = 4.

3 0

3 years ago

Will mark brainliest!!!!!<br> complete this statement<br> 15x^4a^2+20x^2a^3=5x^2a^2 ( )

Angelina_Jolie [31]

$15x^4a^2+20x^2a^3=5x^2a^2 (3x^2+ 4a )$

Answer: 3x² + 4a

5 0

3 years ago

You randomly guess the answers to two questions on a multiple-choice test. Each question has three choices: A, B, and C.

Fantom [35]

Answer: pick a bc its the first lettr of the alphebet

4 0

3 years ago

K + 4(5k +6) = - 123 <br> HELP ASAP

Anni [7]

Answer:

-7

Step-by-step explanation:

-123-(6x4=24)=-147 -147 divided by (4x5k+1k=21k)=-7

4 0

3 years ago

Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles. She can ride 9 mph faster than she can walk. How f

Marrrta [24]

Answer:

$\frac{48}{r+9}=\frac{12}{r}$

Step-by-step explanation:

Let r represent Linda's walking rate.

We have been given that Linda can ride 9 mph faster than she can walk, so Linda's bike riding rate would be $t+9$ miles per hour.

$\text{Time}=\frac{\text{Distance}}{\text{Rate}}$

We have been given that Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles.

$\text{Time while riding}=\frac{48}{r+9}$

$\text{Time taken while walking}=\frac{12}{r}$

Since both times are equal, so we will get:

$\frac{48}{r+9}=\frac{12}{r}$

Therefore, the equation $\frac{48}{r+9}=\frac{12}{r}$ can be used to solve the rates for given problem.

Cross multiply:

$48r=12r+108$

$48r-12r=12r-12r+108$

$36r=108$

$\frac{36r}{36}=\frac{108}{36}$

$r=3$

Therefore, Linda's walking at a rate of 3 miles per hour.

Linda's bike riding rate would be $t+9\Rightarrow 3+9=12$ miles per hour.

Therefore, Linda's riding the bike at a rate of 12 miles per hour.

7 0

3 years ago