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3 years ago

Addinfg in scientific notation 9x10^3 +2.3x10^4=

Mathematics

1 answer:

Vladimir [108]3 years ago

4 0

Answer:

3.2 × 10^4

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10 . If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

3.2 × 10 ^4

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Pls help me!! thank you!!

klasskru [66]

Full working out shown from step 1 to last.

follow it and you get 24 square feet as final answer. Good luck in other questions!!!

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3 years ago

For the function f(x)=|x−7|−4, evaluate f(x+1).

GarryVolchara [31]

Answer:

$\displaystyle{f(x+1)=|x-6|-4}$

Step-by-step explanation:

To evaluate $\displaystyle{f(x+1)}$ , substitute $\displaystyle{x}$ to $\displaystyle{x+1}$ so we should have:

$\displaystyle{f(x+1) = |x+1-7|-4}$

Evaluate the expression and finally, we have:

$\displaystyle{f(x+1)=|x-6|-4}$

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2 years ago

Decide whether the sequence 4,10,20,34,52 ....... is a linear model,

Alecsey [184]

Answer:

Lineal.

Step-by-step explanation:

To determine if the sequence 4,10,20,34,52 ....... is a linear model, a quadratic model or a cubic model, the following mathematical logical reasoning must be carried out:

4 to 10 = +6

10 to 20 = +10

20 to 34 = +14

34 to 52 = +18

Thus, we can see at a glance that the sequence increases 4 numbers in each digit, adding first 6, then 10, then 14 and so on, with which the next numbers in that sequence should be 74 (+22), 100 ( +26), 130 (+30), 164 (+34), and so on.

Therefore, since there is no quadratic or cubic relationship, the sequence is linear.

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3 years ago

Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are

Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

$P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}$ .

Recall that $\binom{n}{k}= \frac{n!}{k!(n-k)!}$ In this case, the student passes if X is at least four correct questions, then

$P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696$

c)The expected value of a binomial random variable with parameters n and p is $E[X] = np$ . IN our case, n=6 and p =0.2. Then the expected value of correct answers is $6\cdot 0.2 = 1.2$