The player will get 10 hits for 15 times strikes out.
The player will strike out 69 times for 46 hits.
Step-by-step explanation:
Given,
Ratio of strike out to hits = 3:2
Condition 1: If the player gets 15 strikes out;
Let,
x be the hits for 15 times strikes out.
Using proportion;
Strike out : hit :: strike out : hit
![3:2::15:x](https://tex.z-dn.net/?f=3%3A2%3A%3A15%3Ax)
Product of mean = Product of extreme
![15*2=3*x\\3x=30](https://tex.z-dn.net/?f=15%2A2%3D3%2Ax%5C%5C3x%3D30)
Dividing both sides by 3;
![\frac{3x}{3}=\frac{30}{3}\\x=10](https://tex.z-dn.net/?f=%5Cfrac%7B3x%7D%7B3%7D%3D%5Cfrac%7B30%7D%7B3%7D%5C%5Cx%3D10)
The player will get 10 hits for 15 times strikes out.
Condition 2: if the player gets 46 hits
Let,
y be the strikes out.
Using proportion,
Strike out : hit :: strike out : hit
![3:2::y:46](https://tex.z-dn.net/?f=3%3A2%3A%3Ay%3A46)
Product of mean = Product of extreme
![2*y=46*3\\2y=138](https://tex.z-dn.net/?f=2%2Ay%3D46%2A3%5C%5C2y%3D138)
Dividing both sides by 2;
![\frac{2y}{2}=\frac{138}{2}\\y=69](https://tex.z-dn.net/?f=%5Cfrac%7B2y%7D%7B2%7D%3D%5Cfrac%7B138%7D%7B2%7D%5C%5Cy%3D69)
The player will strike out 69 times for 46 hits.
Keywords: Ratio, proportion
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