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2 years ago

8

The volume of one of the Great Lakes is 3.5 × 10^3 cubic kilometers. If there are 6.3 × 10^7 fish in the lake, what is the avera

ge number of fish per cubic kilometer?

1 answer:

Gala2k [10]2 years ago

3 0

________________1,8*10^4

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X + 2y when x = 1 and y = 4

Oksanka [162]

Answer:

9

Step-by-step explanation:

x = 1

y = 4

x + 2y = 1 + 8 = 9

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3 years ago

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What is the image of g for a 240° counterclockwise rotation about the center of the regular hexagon

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So for this one, 240 is Two Thirds of 360, which means in a shape with 6 points, it would move four points counterclockwise.
This would move G to the point H
C. H

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2 years ago

2 x 34 x 9 - 6 + 46 plese

Lera25 [3.4K]

answer 652

2 x 34 x 9 - 6 + 46

68 x 9 - 6 + 46

612 - 6 + 46

606 + 46

652

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3 years ago

Solve for x in the equation.

labwork [276]

Answer:

The solution is $\displaystyle x=1\pm \sqrt{47}$ . Fourth option

Explanation:

Solve for x:

$2x^2+3x-7=x^2+5x+39$

Move all the terms from the right to the left side of the equation, a zero in the right side:

$2x^2+3x-7-x^2-5x-39=0$

Join all like terms:

$x^2-2x-46=0$

The general form of the quadratic equation is:

$ax^2+bx+c=0$

Solve the quadratic equation by using the formula:

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

In our equation: a=1, b=-2, c=-46

Substituting into the formula:

$\displaystyle x=\frac{-(-2)\pm \sqrt{(-2)^2-4(1)(-46)}}{2(1)}$

$\displaystyle x=\frac{2\pm \sqrt{4+184}}{2}$

$\displaystyle x=\frac{2\pm \sqrt{188}}{2}$

Since 188=4*47

$\displaystyle x=\frac{2\pm \sqrt{4*47}}{2}$

Take the square root of 4:

$\displaystyle x=\frac{2\pm 2\sqrt{47}}{2}$

Divide by 2:

$\displaystyle x=1\pm \sqrt{47}$

First option: Incorrect. The answer does not match

Second option: Incorrect. The answer does not match

Third option: Incorrect. The answer does not match

Fourth option: Correct. The answer matches exactly this option

8 0

2 years ago

Need help on this one question please

Elan Coil [88]

P(x, y) Q(x,y)
P(-2, -1) start at 0. Go to the left two squares, then go down 1 square. mark a point there
Q(2, 4) start at 0. Go to the right two squares, go up 4 squares. mark a point there.
connect two points
make a right triangle
Then use the pythereom
$4^{2} + 5^{2} = (PQ)^{2}$
$41 = (PQ)^{2}$
$\sqrt{41} = PQ$

6 0

2 years ago