Mind if I have help once more?

Mathematics

1 answer:

Lina20 [59]3 years ago

6 0

$\bf -2=-x+x^2-4\\\\
\begin{array}{llccll}
0=&1x^2&-1x&-2\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\qquad \qquad 
\begin{array}{llll}
\textit{quadratic formula}\\\\
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}
\end{array}$

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Use synthetic division to divide (x3 + 12x2 + 38x + 26) ÷ (x + 4)

KengaRu [80]

Divisor is -4
Use coefficients 1 12 38 26

Bring down 1 multiply by -4 and add to 12 =8
Multiply 8 by -4 and add to 38 = 6
Multiply 6 by -4 and add to 26 = 2 which is the remainder

looks like 1 12 38 26
-4 -32 -24
________________
1 8 6 R 2
so answer A of x squared + 8x + 6 +R2 is correct

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The domain of f(x) is the set of all real values except 7 , and the domain of g(x) is the set of all real values except -3. Witc

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Answer: <span><span>the domain of g [f(x) ] is the set of all real values except 7 and the x for which f(x) = - 3.</span>

Explanation:

Taking (g•f)(x) as (g o f) (x), this is g (x) composed with f(x) you have this analysis.

(g o f) (x) is g [ f(x) ], which means that you first apply the function f and then apply the function g to the output of f(x).

The domain of g [ f(x) ] has to exclude 7, because it is not included in the domain of f(x).

Also the domain thas to exclude those values of x for which f(x) is - 3, because the domain of g(x) is the set of all real values except - 3.

So, the domain of g [f(x) ] is the set of all real values except 7 and the x for which f(x) = - 3.

</span>

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Actually I had learnt this but.....do u want a formula ?

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vladimir2022 [97]

Answer:

Step-by-step explanation:

Given that spinner contains four sections: red, blue, green, and yellow. Joaquin spins the spinner twice. The set of outcomes is given as

S = {RB, RG, RY, RR, BR, BG, BY, BB, GR, GB, GY, GG, YR, YB, YG, YY}.

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