How could you calculate each product? Describe the strategy you would use. Then calculate.

The cost of tuition at a college is $12,000 and is increasing at the rate of 6% each year. Use exponential function to find the

Gnesinka [82]

Answer:

The cost of tuition fee after 4 years is $15,149.72.

Step-by-step explanation:

Exponential function:

$A=P(1+r)^n$

A= the amount after n years

P= Initial amount

r= rate of increasing

n= time in years

The cost of tuition at a college is $12,000. It is increasing at the rate of 6% each year.

Here, P= $12,000, r= 6%= 0.06, n= 4 years.

$\therefore A=12,000(1+0.06)^4$

$\Rightarrow A= 12000(1.06)^4$

=$15,149.72

The cost of tuition fee after 4 years is $15,149.72.

7 0

4 years ago

A safety officer wants to prove that μ = the average speed of cars driven by a school is less than 25 mph. Suppose that a random

melomori [17]

Answer:

$t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70$

$p_v =P(t_{(13)}$

If we compare the p value and the significance level given $\alpha=0.05$ and we can see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can't conclude that the true average speed is lower than 25 mph at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=24$ represent the sample mean

$s=2.2$ represent the sample standard deviation

$n=14$ sample size

$\mu_o =25$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean for the average speed is lower than 25 mph, the system of hypothesis would be:

Null hypothesis: $\mu \geq 25$

Alternative hypothesis: $\mu < 25$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=14-1=13$

Since is a one side test the p value would be:

$p_v =P(t_{(13)}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ and we can see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can't conclude that the true average speed is lower than 25 mph at 5% of signficance.

7 0

3 years ago

PLEASE HELP ACED + +++++++++

iVinArrow [24]

Don’t click that link

3 0

3 years ago

A bank is investigating ways to entice customers to charge more on their credit cards. (Banks earn a fee from the merchant on ea

MAVERICK [17]

Answer:

$CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\$

$CI = (527 - 439) \pm 25.75\\\\CI = 88 \pm 25.75\\\\CI = 88 - 25.75 \:\: and \:\: 88 + 25.75\\\\CI = (62.2 \: ,\: 113.8 )$

The correct answer choice is a. (62.2, 113.8)

Step-by-step explanation:

Of the 500 customers who were told the increase applied to charges above $1000 each month, the average increase in spending was $527 with a standard deviation of $225.

Sample size = n₁ = 500

Sample mean = x₁ = $527

Standard deviation = s₁ = $225

Of the 500 customers who were told the increase applied to charges above $2000 each month, the average increase in spending was $439 with a standard deviation of $189

Sample size = n₂ = 500

Sample mean = x₂ = $439

Standard deviation = s₂ = $189

We are asked to find the 95% confidence interval for the difference between two means.

The given group of answer choices are

a. (62.2, 113.8)

b. (86.2, 120.5)

c. (10.3, 23.8)

d. (55.6, 67.8)

The confidence interval for the difference between two means is given by

$CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\$

Where $\bar{x_{1} }$ and $\bar{x_{2} }$ are the given sample means and margin of error is given by

$MoE = z_{\alpha/2} \cdot \sqrt{\frac{s_{1}^2}{n_1} + \frac{s_{2}^2}{n_2}}$

The z-score corresponding to 95% confidence level is given by

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

From the z-table at α = 0.025 the z-score is 1.96

$MoE = 1.96 \cdot \sqrt{\frac{225^2}{500} + \frac{189^2}{500}}$

$MoE = 1.96 \cdot 13.14$

$MoE = 25.75$

Finally,

$CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\$

$CI = (527 - 439) \pm 25.75\\\\CI = 88 \pm 25.75\\\\CI = 88 - 25.75 \:\: and \:\: 88 + 25.75\\\\CI = (62.2 \: ,\: 113.8 )$

Therefore, the correct answer choice is a. (62.2, 113.8)

How to use z-table?

In the z-table find the probability of 0.025

Note down the value of that row, it would be 1.9.

Note down the value of that column, it would be 0.06.

Add the two numbers together.

The z-score is 1.9 + 0.06 = 1.96

4 0

4 years ago

Cells B1, C1, and D1 contain the values Seat1Row1, Seat1Row2, and Seat1Row3. If cells B1, C1, and D1 were selected, and autofill

Reil [10]

Answer:

The autofilled values would be Seat1Row4, Seat1Row5, Seat1Row6

Step-by-step explanation:

Given

B1 = Seat1Row1

C1 = Seat1Row2

D1 = Seat1Row3

Required

Values of E1, F1, G1 if autofilled

Autofill in Microsoft Office Excel (Ms Excel).is used to automatically fill cells base on suggestion from previous cells.

The autofill feature of Ms Excel works data types such as numbers and alphanumeric among others.

But for autofill to work on alphanumeric in Ms Excel, only the numeric part will be altered.

In this case, the series of text in B1, C1 and D1 are Seat1Row1, Seat1Row2, Seat1Row3

"Seat1Row" will be regarded as string while 1,2,3 will be incremented and the resulting alphanumeric values will be saved in their respective cells.

Hence,

Cell E1 will be filled with Seat1Row4

F1 will be filled with Seat1Row5

G1 will be filled with Seat1Row6

See attachment

6 0

3 years ago

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