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Annette [7]
4 years ago
8

Please help on 8-9 I'm desperate :/

Mathematics
1 answer:
slava [35]4 years ago
7 0

8. 20-11+m

9. 30-17=h

Hope you get an A+

You might be interested in
Evaluate f(-12) given f(x) = -21x - 12
frozen [14]

Answer:

The answer for the given function is f( -12 ) = 240.

Step-by-step explanation:

Given:

f(x)=-21x-12

To Find :

F ( -12 ) = ?

Solution:

Function:

  1. A function is like a machine that gives an output for a given input.
  2. A function has an independent variable which is called the input of the function.
  3. The output for a given input is called the dependent variable.

For Example

f ( x ) = x + 3

x = independent variable

f ( x ) = Output for a given input

Here we have

f(x)=-21x-12\\Put\ x=-21\\\therefore f(-12) = -21\times -12 - 12\\\therefore f(-12) = 252 - 12\\\therefore f(-12) = 240

Therefore f(-12) = 240

8 0
3 years ago
Read 2 more answers
A soccer field is rectangular and measures 100 yards by 60 yards. a soccer ball is randomly kicked onto the field. if it is equa
geniusboy [140]
The answer is: b. 5%

You multiply 100 x 60 to get 6000
You then get the radius by doing A = π*r^2 = πd^2/4 which is 314.159 (rounded).

Divide 314.159 and 6000 to get 0.05235 or 5%.
5 0
3 years ago
Explain why Rolle's Theorem does not apply to the function even though there exist a and b such that f(a)
Anna35 [415]

Rolle's Theorem does not apply to the function because there are points on the interval (a,b) where f is not differentiable.

Given the function is f(x)=\sqrt{(2-x^{\frac{2}{3}})^{3}}  and the Rolle's Theorem does not apply to the function.

Rolle's theorem is used to determine if a function is continuous and also differentiable.

The condition for Rolle's theorem to be true as:

  • f(a)=f(b)
  • f(x) must be continuous in [a,b].
  • f(x) must be differentiable in (a,b).

To apply the Rolle’s Theorem we need to have function that is differentiable on the given open interval.

If we look closely at the given function we can see that the first derivative of the given function is:

\begin{aligned}f(x)&=\sqrt{(2-x^{\frac{2}{3}})^3}\\ f(x)&=(2-x^{\frac{2}{3}})^{\frac{3}{2}}\\ f'(x)&=\frac{3}{2}(2-x^{\frac{2}{3}})^{\frac{1}{2}}\cdot \frac{2}{3}\cdot (-x)^{\frac{1}{3}}\\ f'(x)&=\frac{-\sqrt{2-x^{\frac{2}{3}}}}{\sqrt[3]{x}}\end

From this point of view we can see that the given function is not defined for x=0.

Hence, all the assumptions are not satisfied we can reach a conclusion that we cannot apply the Rolle's Theorem.

Learn more about Rolle's Theorem from here brainly.com/question/12279222

#SPJ4

8 0
2 years ago
Please help me what is the measure of it ?
never [62]

Answer:

115

Step-by-step explanation:

A supplementary line equals 180

You have to subtract 65 by 180

which gives you 115

7 0
3 years ago
I need help on this question, someone please help!!
Tju [1.3M]

Answer:

y=−x−1/3x−8

Step-by-step explanation:

y=8x−1/3x+1

To find the inverse function, swap x and y, and solve the resulting equation for x.

If the initial function is not one-to-one, then there will be more than one inverse.

So, swap the variables: y=8x−1/3x+1 becomes x=8y−1/3y+1.

Now, solve the equation x=8y−1/3y+1 for y.

y=−x−1/3x−8

Sorry I was in a rush and couldn't do the fractions as formulae. Hope it helped anyways.

7 0
3 years ago
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