Answer:
Step-by-step explanation:
Any time you have compounding more than once a year (which is annually), unless we are talking about compounding continuously, you will use the formula
Here's what we have:
The amount after a certain time that she has in the bank is 4672.12; that's A(t).
The interest rate in decimal form is .18; that's r.
The number of times the interest compounds is 12; that's n
and the time that the money is invested is 3.5 years; that's t.
Filling all that into the formula:
Simplifying it down a bit:
Raise 1.015 to the 42nd power to get
4672.12 = P(1.868847115) and divide to get P alone:
P = 2500.00
She invested $2500.00 initially.
$34 divided by 4 = $8.5 per hour.
$8.5 Times 10 hours = $85
So she would earn $85
Answer:
The greatest rate of change is for <u>school A</u> as it has the greatest ratio of 2.5
Step-by-step explanation:
School A:
Ratio of male to female students, 
School B:
Male students are related to female students by equation:
Where, 
means number of female students and 
means number of male students.
Therefore, the ratio of male to female students is, 
School C:
Ratio of male to female students is, 
Now, rate of change of male to female students is directly proportional to the ratio of the two.
Hence, the greater the ratio, the greater the rate of change.
So, the greatest rate of change is for school A as it has the greatest ratio of 2.5
I cannot reach a meaningful solution from the given information. To prove that S was always true, you would have to prove that N was always false. To prove that N was always false you would have to prove that L was always false. For the statement (L ^ T) -> K to be true, you only need K to be true, so L can be either true or false.
Therefore, because of the aforementioned knowledge, I do not believe that you can prove S to be true.
I really don’t know gang but be strong you can do it
