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2 years ago

What’s the untit rate for 400 miles on 20 gallons

Mathematics

1 answer:

victus00 [196]2 years ago

6 0

Answer:

20 miles per gallon

Step-by-step explanation:

We want a unit rate where

1 is in the denominator

so we divide top and bottom by 20

$\frac{400 miles/20}{20 gallons/20}$ = $\frac{20 miles}{1 gallon}$ = 20 miles a gallon

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NemiM [27]

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3 years ago

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bagirrra123 [75]

Answer:

x ≈ 3.1 ft

Step-by-step explanation:

The segment from the centre to the chord is a perpendicular bisector, thus

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3 years ago

Simplify for a lot of points<br> (1-sin^2x)(1-tan^2x)

notka56 [123]

1/sin^2x-1/tan^2x=
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4 years ago

A car is brought for $28 000.00 and it will depreciate at a rate of $100 per month.

yawa3891 [41]

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4 years ago

In a geometric sequence, a4 = 54 and a7 = 1,458. what is the 12th term? <br><br> answer: B) 354,294

slamgirl [31]

Option B:

The 12th term is 354294.

Solution:

Given data:

$a_4=54$ and $a_7=1458$

To find $a_{12}:$

The given sequence is a geometric sequence.

The general term of the geometric sequence is $a_n=a_1\ r^{n-1}$ .

If we have 2 terms of a geometric sequence $a_n$ and $a_k$ (n > K),

then we can write the general term as $a_n=a_k\ r^{n-k}$ .

Here we have $a_4=54$ and $a_7=1458$ .

So, n = 7 and k = 4 ( 7 > 4)

$a_7=a_4\ .\ r^{7-4}$

$1458=54\ . \ r^3$

This can be written as

$$r^3=\frac{1458}{54}$

$$r^3=27$

$$r^3=3^3$

Taking cube root on both sides of the equation, we get

r = 3

$a_{12}=a_7\ .\ r^{12-7}$

$=1458\ .\ r^5$

$=1458\ .\ 3^5$

$a_{12}=354294$

Hence the 12th term of the geometric sequence is 354294.

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3 years ago